The curve is y equals 0 from negative x to negative y near x equals negative 8.
If a curve has Vertical Asymptote i.e the line x=p,it is never touched by the given curve.The curve remains almost parallel to the line x=p, till the end.The two i.e a line and curve will never meet each other.
→ x is almost equal to p but not p.
so in the denominator , it is x=-8,
Vertical Asymptote occurs when we put , denominator of curve=0.
so vertical asymptote of curve is : x= -8
Answer:
An equation of the circle with centre (-2,1) and radius 3 is 
Option D is correct.
Step-by-step explanation:
Looking at the figure we get centre of circle C (-2,1) and radius of circle r = 3
The equation of circle is of form:
where (h,k) is centre and r is radius.
We have centre C (-2,1) so, we have h = -2 and k = 1
We have radius = 3 so, r = 3
Putting values in the equation and finding the required equation:

So, an equation of the circle with centre (-2,1) and radius 3 is 
Option D is correct.
I assume each path
is oriented positively/counterclockwise.
(a) Parameterize
by

with
. Then the line element is

and the integral reduces to

The integrand is symmetric about
, so

Substitute
and
. Then we get

(b) Parameterize
by

with
. Then

and

Integrate by parts with



(c) Parameterize
by

with
. Then

and

Answer:
The answer will be A.
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
4x-1=-4
-4+3=-1