Question

Evaluate the geometric series. Round to the nearest hundredth. Please help ASAP!!!

Answer 1

Answer:

Rounded to the nearest hundredth, the answer is 10.67.

Step-by-step explanation:

To obtain this answer, you have to take the summation from n=1 to n=10 of $8(\frac{1}{4})^{n-1}$ by plugging in n=1 into the equation, then n=2, so on and so forth, all the way up to n=10, and adding those all together. Done by hand, this would look like:

$8(\frac{1}{4})^{1-1}+8(\frac{1}{4})^{2-1}+8(\frac{1}{4})^{3-1}+8(\frac{1}{4})^{4-1}+8(\frac{1}{4})^{5-1}+8(\frac{1}{4})^{6-1}+8(\frac{1}{4})^{7-1}+8(\frac{1}{4})^{8-1}+8(\frac{1}{4})^{9-1}+8(\frac{1}{4})^{10-1}=(approximately) 10.67$