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3 years ago

The perimeter of a semicircle is 51.4 meters. What is the semicircle's radius? Use 3.14 for .

Mathematics

1 answer:

Vadim26 [7]3 years ago

3 0

The radius is 8.31 cm long

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suppose a triangle has two sides of length 2 and 3 and that the angle between these two sides is 60. what is the length of the t

arlik [135]

Answer:

√7 ≈ 2.646

Step-by-step explanation:

The law of cosines is applicable. It tells you ...

c² = a² + b² - 2ab·cos(C) . . . . . where a, b, c are triangle side lengths, and angle C is opposite side c.

Filling in the given information, you have ...

c² = 2² + 3² - 2·2·3·cos(60°) = 4 + 9 - 12·(1/2) = 7

c = √7 ≈ 2.646

The length of the third side is √7, about 2.646 units.

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3 years ago

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Show work please! I don't understand how to get this answer! I will give brainliest to the best answer!

Marina86 [1]

Answer:

(x,y,z) = (2,-2,1)

Step-by-step explanation:

Three equations with three variables are given. Take two equations at a time to eliminate one variable.

x + y - z = -1 .....(1)

4x -3y + 2z = 16 .....(2)

2x - 2y - 3z = 5 ......(3)

Solve (1) and (3) to eliminate z.

To do that multiply (1) by 2 and add (1) and (2). We get:

4x - 5z = 3 ......(4)

Now, solve (2) and (3) and subtract them. We get:

2x + 13z = 17 ......(5)

Solve (4) and (5). Multiply (5) by 2 and subtract. We get:

z = 1

Substituting z = 1, in (4) we get: x = 2.

Now to find y, substitute values of x and y in (1).

⇒ x + y - z = -1 ⇒ 2 + y - 1 = -1

⇒ y = -2

∴ Values of (x, y, z) = (2, -2, 1).

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3 years ago

Option 1: $30 an hour plus a nonrefundable deposit of $50

Aleks [24]

Answer:

to be honost i am in 8th grade but i realy like you and your the first person i like in a lot of time

Step-by-step explanation:

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3 years ago

What is y=2x+5 in standard form?

baherus [9]

My guess is 2x-y= -5

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3 years ago

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Help please!<br><br> | 2x^2 + 5x + 3 | > 0<br> solve the inequality

vovikov84 [41]

Factorize the quadratic.

$2x^2 + 5x + 3 = (2x + 3) (x + 1)$

We have $|ab| = |a||b|$ , so

$|2x^2 + 5x + 3| = |2x + 3| |x + 1| > 0$

Now, both $|2x+3|\ge0$ and $|x+1|\ge0$ (since the absolute value of any number cannot be negative), so we just need to worry about when the left side is exactly zero. This happens for

$(2x + 3) (x + 1) = 0 \implies 2x+3 = 0\text{ or }x+1 = 0 \\\\ \implies x = -\dfrac32 \text{ or } x = -1$

So the solution to the inequality is the set

$\left\{x \in \Bbb R \mid x\neq-\dfrac32 \text{ and } x\neq-1\right\}$

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2 years ago

The perimeter of a semicircle is 51.4 meters. What is the semicircle's radius? Use 3.14 for ​.

The perimeter of a semicircle is 51.4 meters. What is the semicircle's radius? Use 3.14 for .