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Nat2105 [25]
3 years ago
6

You start at (5, -2). You move left 5 units and up 6 units. Where do you end?

Mathematics
1 answer:
Mila [183]3 years ago
4 0

(0,5) is your answer

Hope this helped and is correct

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What is the measurement of ∠2 and ∠11?
notsponge [240]

Answer:

180

Step-by-step explanation:

You measure the size of an angle with a protractor. Or could be shown by an arc on the figure to indicate which angles that are congruent. Two angles whose measures together are 180° are called supplementary e.g. two right angles are supplementary since 90° + 90° = 180°.

3 0
2 years ago
Sally took $13 to the movies. She paid $5 for a movie ticket and popcorn. Which number sentence below will tell how much money s
Alla [95]

Answer:

n = 13 - 5

Step-by-step explanation:

Given,

Amount of money Sally had at first = $13

Amount of money Sally Spent = $5

amount of money left over, n

= Amount of money Sally had at first - Amount of money she spent

= 13 - 5

hence

n = 13 - 5

6 0
2 years ago
A company pays $10 per hour for up to 8 hours of work. What is the equation for total pay (y) for hours worked (x), for 0-8 hour
Margaret [11]

Answer:

iwill edit

Step-by-step explanation:

6 0
2 years ago
Any help with this greatly appreciated.
Anestetic [448]

Put the equation in standard linear form.

x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}

Find the integrating factor.

\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5

Multiply both sides by \mu.

(t+5) x'(t) + x(t) = 5(t+5)e^{5t}

Now the left side the derivative of a product,

\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}

Integrate both sides.

(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt

On the right side, integrate by parts.

(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C

Solve for x(t).

\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}

3 0
2 years ago
PLEASE HELP AND ANSWER THE QUESTION IN FULL WILL GIVE BRAIN
Murrr4er [49]

Answer:

I think it might be data and range

Step-by-step explanation:

the answer is at the top

7 0
2 years ago
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