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Leno4ka [110]
3 years ago
15

Evaluate h(d) =4/9d+6 2/3 for d=3 A. 8 B. 7 C.7 1/3 D. 2 2/3

Mathematics
1 answer:
iragen [17]3 years ago
8 0

For this case we have a function of the form y = h (d). Where:

h (d) = \frac {4} {9} d + 6 \frac {2} {3}

Rewriting the mixed number as a fraction:

h (d) = \frac {4} {9} d + \frac {3 * 6 + 2} {3}\\h (d) = \frac {4} {9} d + \frac {20} {3}

Substituting d = 3:

h (3) = \frac {4} {9} (3) + \frac {20} {3}\\h (3) = \frac {4} {3} + \frac {20} {3}\\h (3) = \frac {24} {3}\\h (3) = 8

ANswer:

Option A

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