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pychu [463]
3 years ago
8

How many $0.21 pencils can be purchased for $7.00? Show your work.

Mathematics
2 answers:
IgorLugansk [536]3 years ago
8 0
N*(21/100)=(700/100)

n=(700/100)/(21/100)

n=(700/100)*(100/21)

n=700/21

n=33+1/3

So <em><u>thirty three</u></em> $0.21 pencils can be purchased for $7.00.
rewona [7]3 years ago
4 0

You can divide $7.00 by $ .21

7 ÷ .21 = 33.3333333

 So you can buy 33 pencils for $7.00

Hope this helps you. :-)

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nignag [31]

Answer:

6 shelves

Step-by-step explanation:

3/8 = 6/16

6/16 divided by 1/16

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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
which rate can you set 7 miles over 1 hour equal to in order to find the distance traveled in 49 hours at 7 miles per hour
IrinaVladis [17]

Answer:

Step-by-step explanation:

time = 49 hours

speed =  7 miles/hour

speed = distance / time

∴ distance = speed × time

= 7 × 49

= 343 miles

8 0
3 years ago
4 times a number is 32 less than the square of that number. Find the negative solution.
zvonat [6]

Answer:

<u>The negative solution is -4</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

x = a number

4x = x² - 32 (4 times a number is 32 less than the square of that number)

2. Let's solve for x and find the negative solution:

4x = x² - 32

-x² + 4x + 32 = 0

x² - 4x - 32 = 0 (Multiplying by - 1)

(x - 8) (x + 4) = 0

(x₁  - 8) = 0

(x₂ + 4) = 0

x₁ = 8

<u>x₂ = -4</u>

<u>The negative solution is -4</u>

3 0
2 years ago
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