Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
3.141592654...
Step-by-step explanation:
it just keeps going and going and never stops.
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N=3
Because 6+6=12
Hope this helps
Given:
The slope of a line is 
.
To find:
The lines in the options are parallel, perpendicular or neither parallel nor perpendicular to the given line.
Solution:
We know that the slopes of parallel lines are equal.
The slope of line Q and the slope of given line are same, i.e., . So, the line Q is parallel to the given line.
The slope of a perpendicular line is the opposite reciprocal of the slope of the line because the product of slopes of two perpendicular lines is -1.
The slope of a line is . It means the slope of the perpendicular line must be 
. So, the line N is perpendicular to the given line.
The slopes of line M and P are neither equal to the slope of the given line nor opposite reciprocal of the slope of the line.
Therefore, the lines M and P are neither parallel nor perpendicular.
Answer:
n=12
Step-by-step explanation:
bc im always right
