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Fudgin [204]
4 years ago
9

A regular polygon has 15 sides. Which is a possible angle of rotational sym

Mathematics
1 answer:
coldgirl [10]4 years ago
6 0

Answer: if i did my math correctly, 72 degrees is ur answer.

Step-by-step explanation:

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2+2. Wwwwwwwwwwwwwwwwwwwewwww
Andrews [41]

Answer:

4

Step-by-step explanation:

2+2+ 4 you have two hands put two fingers up on each of them count them!

6 0
4 years ago
Read 2 more answers
I'm really confused I'm not that good in math
yKpoI14uk [10]

Answer:

pretty sure it's -4.5

Step-by-step explanation:

idk mate, just used calculator

8 0
3 years ago
PLEASE HELP!! URGENT
Slav-nsk [51]

1. The problem statement tells you to find "the area of the hexagonal face".

2. If we assume the intent is to find the shaded area of the face only, it differs from the area of a regular hexagon in that there is a hole in the middle.

3. You must find the area of the regular hexagon, and subtract the area of the circular hole in the middle.

4. The formula for the area of a circle in terms of its radius is

... A = πr²

5. The formula for the area of a regular hexagon in terms of the radius of the circumcircle is

... A = (3√3)/2·r²

6. The radius of the circumcircle of the regular hexagon is given. No additional information is needed.

7. You can use the trig functions of the angles of an equilateral triangle to find the apothem, but there is no need for that when you use the formula of 5.

8. All this is unnecessary. The apothem is (8 mm)·(√3)/2 = 4√3 mm ≈ 6.9282 mm, the shorter leg is (8 mm)·(1/2) = 4 mm. The perimeter is 6·8 mm = 48 mm.

9. The area of the hexagon is

... A = 3√3/2·(8 mm)² = 96√3 mm² ≈ 166.277 mm²

10. The area of the circle is

... A = π·(4 mm)² = 16π mm² ≈ 50.265 mm²

11. The area of the hexagonal face is approximately ...

... 166.277 mm² - 50.265 mm² = 116.01 mm²

6 0
3 years ago
Find the area. Simplify the answer. 3x and x+6
Ilya [14]
18x .......,,,,..xbxncmd
5 0
3 years ago
Two horses are ready to return to their barn after a long workout session at the track. The horses are at coordinates H(1,10) an
lana [24]
Distance between points \left(x_1,y_1\right) and \left( x_2,y_2 \right) is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Distance from H to B:

[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.

Distance from Z to B:

d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269} units.

Horse Z is closer to the barn.

(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
6 0
4 years ago
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