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Harrizon [31]
3 years ago
15

A student made this model of a carbon dioxide molecule. its has one carbon atom and two oxygen atoms what is the correct way to

write the chemical name of carbon dioxide
Chemistry
2 answers:
ExtremeBDS [4]3 years ago
4 0
The proper way to chemically write carbon dioxide is CO2
evablogger [386]3 years ago
4 0

Answer:

The chemical name of carbon dioxide is CO_2.

Explanation:

C+2O\rightarrow CO_2

In a model of carbon dioxide made by the student there are one carbon atom and two oxygen atoms which means that total atoms in the molecule of carbon-dioxide is three.

While writing the chemical name of the carbon dioxide we will first write the symbol of the electropositive atom and then electronegative atom:CO_2

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About 6.5x10^22 molecules. (5g C2H5OH)x(1 mol C2H5OH/46g C2H5OH)x(6.02x10^23 molecules C2H5OH/1 mol C2H5OH)=(3.01E24)/46=6.5x10^22. Let me know if this helped!
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Define the word isotope​
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Isotope, one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behaviour but with different atomic masses and physical properties.

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Near the shore, winds tend to blow out toward the water at night. What drives this process?
Mila [183]

C. Convection currents in the air

Explanation:

Near the shore, winds tends to blow out towards the water at night and this is driven by convection currents in the air.

Convection occurs in fluids. Since we are dealing with wind, therefore, it is convection in air.

  • At night, the air on land is cold and under high pressure.
  • The shore area is able lose and gain heat very fast.
  • At night, since the shore is cold, the air around is cold too.
  • The ocean has high heat capacity and does not lose or gain heat easily.
  • At night, it still retains come of its heat.
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8 0
3 years ago
A hot air balloon is filled with 1.31 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 121 ∘ C . Wha
victus00 [196]

Answer:

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

Explanation:

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2} (at constant pressure)

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1= 1.31\times 10^6 L\\T_1=11^oC=(11+273.15)K=284.15K\\V_2=?\\T_2=121^oC=(121+273.15)K=394.15 K

Putting values in above equation, we get:

\frac{1.31\times 10^6 L}{284.15 K}=\frac{V_2}{394.14 K}\\\\V_2=\frac{V_1\times T_2}{T_1}

V_2=1.82\times 10^6 L

1.82\times 10^6 L is the volume of the air in the balloon after it is heated.

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3 years ago
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