Answer : The theoretical yield of water in this reaction is 360 g.
Solution : Given,
Mass of
Mass of
Mass of
Molar mass of = 44 g/mole
Molar mass of = 24 g/mole
Molar mass of = 18 g/mole
First we have to calculate the moles of and .
Moles of =
Moles of =
The given balanced chemical reaction is,
From the given reaction, we conclude that
1 mole of react with 2 mole of
20 moles of requires of
But the actual moles of = 42 moles
Excess moles of = 42 - 40 = 2 moles
So, is the limiting reagent.
Now we have to calculate the mass of .
From the reaction, we conclude that
1 mole of gives 1 mole of
20 moles of gives 20 moles of
Mass of = Moles of × Molar mass of
Mass of = 20 moles × 18 g/mole = 360 g
The experimental yield of = 325 g
Therefore, the theoretical yield of = 360 g
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