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3 years ago

15

What is the vertex of the parabola? y + 4 = 1/2 (x - 7)^2Please help fast !

1 answer:

Ber [7]3 years ago

8 0

Get into form (x-h)^2=4p(y-k)
vetex is (h,k)

so
1/2(x-7)^2=y+4
times 2 both sides
(x-7)^2=2(y+4)
(x-7)^2=4(1/2)(y-(-4))
vertex is (7,-4)

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2 years ago

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3 years ago

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tekilochka [14]

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Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet

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Step-by-step explanation:

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Using Pythagoras theorem:

$hypotenuse^2=perpendicular^2+base^2$

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Taking square root on both sides.

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In a right angled triangle

$\sin \theta = \dfrac{opposite}{hypotenuse}$

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$\sec \theta = \dfrac{hypotenuse}{adjacent}$

$\sec \theta = \dfrac{13}{12}$

In second quadrant only sine and cosecant are positive.

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3 years ago