Answer:
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
||Vel_jet_r|| = 465.993 mph
Step-by-step explanation:
We need to decompose the velocity of the wind into a component that can be added (or subtracted from the velocity of the jet)
The velocity of the jet
500 mph North
Velocity of the wind
50 mph SouthEast = 50 cos(45) East + 50 sin (45) South
South = - North
Vel_ wind = 50 cos(45) mph East - 50 sin (45) mph North
Vel _wind = 35.35 mph East - 35.35 mph North
This means that the resulting velocity of the jet is equal to
Vel_jet_r = (500 mph - 35.35 mph) North + 35.35 mph East
Vel_jet_r = (464.645 mph) North + (35.35 mph) East
An the jet has a magnitude velocity of
||Vel_jet_r|| = sqrt ((464.645 mph)^2 + (35.35 mph)^2)
||Vel_jet_r|| = 465.993 mph
Answer:
280 ft squared
Step-by-step explanation:
To find the area of the nonshaded portion, we can find the area of the entire floor and then subtract the shaded area.
The total area is that of a rectangle: 30 * 15 = 450 ft squared.
Now, the shaded region is made up of a rectangle and a triangle.
- The rectangle has length 8 and width 10, so its area is 10 * 8 = 80 ft squared.
- The triangle has base 12 and height 15, so using the area of a triangle formula: 
(where b is the base and h is the height) = (12 * 15)/2 = 180/2 = 90 ft squared.
- The total shaded region is: 80 + 90 = 170 ft squared
Subtract 110 from 450: 450 - 170 = 280 ft squared.
Thus, the answer is 280 ft squared.
Hope this helps!
Answer:
Step-by-step explanation A line of best fit is often useful to attempt to represent data with the equation of a straight line in order to predict values that may not be displayed on the plot.n:
Answer:
y = 5/3
Step-by-step explanation:
2y + 2/3 = 4
<u>Step 1: Solve for y by subtracting 2/3 from both sides</u>
2y + 2/3 - 2/3 = 4 - 2/3
2y / 2 = 10/3 / 2
y = 10/6
<em>y = 5/3</em>
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Answer: y = 5/3
