Answer:D
Step-by-step explanation:
Sorry Ik it’s to late lol
Answer:

Step-by-step explanation:
A line with the highest absolute value of slope has the steepest graph
from the option, the highest is 5/2 so, y = 5/2 x is your answer.
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If you are asking what is the graph of y = 3x^2 -2x+1.
Then, the attached file would be the answer.
To check, b^2 - 4(a)(c), for each equation and use these facts:
If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.
If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.
If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots.
Answer:
cos (105°) = - 2.6
csc (105°) = 1.03
Step-by-step explanation:
Given that cos (-105°) = - 0.26 {The negative sign is due to the angle - 105° lies in the third quadrant where cos value is negative}
Again, given that csc (- 105°) = - 1.03 {{The negative sign is due to the angle - 105° lies in the third quadrant where csc value is negative}
Now, cos (105°) = - 2.6, because 105° lies in the second quadrant and here cos value is negative.
And csc (105°) = 1.03, because 105° lies in the second quadrant and here csc value is positive. (Answer)