Answer:
No real solutions
Step-by-step explanation:
Use the discriminant to determine the number of real solutions to a quadratic equation.
The general form for a quadratic equation is ax² + bx + c
The discriminant is b² - 4ac
The following 3 rules apply...
1. If b² - 4ac > 0, then there are 2 real solutions
2. If b² - 4ac = 0, then there is one real solution
3. If b² - 4ac < 0 then there are no real solutions
For this problem,
a = 5
b = 6
c = 4
Plug them into b² - 4ac....
6² - 4(5)(4)
36 - 80
-54 so b² - 4ac < 0 , there are no real solutions
