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erica [24]
3 years ago
5

How many real solutions are there to 5x^2+6x+4=0?

Mathematics
1 answer:
zimovet [89]3 years ago
7 0

Answer:

No real solutions

Step-by-step explanation:

Use the discriminant to determine the number of real solutions to a quadratic equation.  

The general form for a quadratic equation is ax² + bx + c

The discriminant is    b² - 4ac

The following 3 rules apply...

1. If  b² - 4ac > 0, then there are 2 real solutions

2. If  b² - 4ac = 0, then there is one real solution

3. If  b² - 4ac < 0 then there are no real solutions

For this problem,

a = 5

b = 6

c = 4

Plug them into  b² - 4ac....

6² - 4(5)(4)

  36 - 80

   

       -54           so  b² - 4ac < 0 , there are no real solutions  

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Answer:

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Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

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3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

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Replacing l*w in (3) with A₁ from (1):

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Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

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