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maria [59]
2 years ago
11

What is the first step in constructing an inscribed circle inside triangle XYZ?

Mathematics
1 answer:
Tasya [4]2 years ago
6 0

Answer:

Construct the angle bisector of angle Y

Step-by-step explanation:

-An inscribed circle is defined as the largest circle that can be drawn within the boundaries of a plane figure.

-The first step in constructing an inscribed circle is to bisect any two angles of the plane figure, triangle in this case, as there intersection point will form the circle's center.

=>Hence, the first step is Construct the angle bisector of angle Y or Z or X( whichever you decide on).

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Pleaseee I need help on this one too
erastova [34]
I can't exactly see if the 10 at the end is negative, but I'm going to assume that it is.
10x - 6y = 8
5x - 10y = -10
= (2, 2)
} I hope this helped! {
5 0
3 years ago
What is X when 19,695 divided by X-15,605 = 100
Zepler [3.9K]

Step-by-step explanation:

\frac{19695}{x - 15605}  = 100

19695 = 100(x - 15605)

19695 = 100x - 1560500

19695 + 1560500 = 100x

15801 95 = 100x

\frac{1580195}{100}  = x

x = 15801.95

3 0
2 years ago
Name 3 numbers between 0.33 and 0.34
Tamiku [17]

0.331

0.332

0.333

There you go.

3 0
3 years ago
Read 2 more answers
QUICK<br><br> Find the area of the shaded region. Use 3.14 for pi.
ivolga24 [154]

Answer:

The shaded region is 353.25m^2.

Step-by-step explanation:

The area of a circle is defined by the multiplication of the square of its radius, or half its diameter, by pi, or simply A=\pi r^2.

15m is the radius of the large circle, and also the diameter of the smaller circles.

The area of the shaded region will be the subtraction of the area of the two smaller circles from the area of the larger circle.

As such:

A=\pi(15)^{2}-2(\pi(\frac{15}{2} )^{2})\\\\A=(3.14)(15)^{2}-2(3.14)(\frac{15}{2} )^{2}\\A=706.5-353.25\\A=353.25

4 0
2 years ago
Read 2 more answers
Which is the length of the arc MPN expressed in terms of pie?
Luba_88 [7]

Answer:

\frac{79}{9} \pi

Step-by-step explanation:

3 0
2 years ago
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