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2 years ago

What is the first step in constructing an inscribed circle inside triangle XYZ?

Mathematics

1 answer:

Tasya [4]2 years ago

6 0

Answer:

Construct the angle bisector of angle Y

Step-by-step explanation:

-An inscribed circle is defined as the largest circle that can be drawn within the boundaries of a plane figure.

-The first step in constructing an inscribed circle is to bisect any two angles of the plane figure, triangle in this case, as there intersection point will form the circle's center.

=>Hence, the first step is Construct the angle bisector of angle Y or Z or X( whichever you decide on).

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A right cylinder has a radius of 5 and a height of 9. What is its surface area?

harkovskaia [24]

Answer:

B. 140π units²

Step-by-step explanation:

Surface area of a cylinder:

2πrh + 2πr²

2π(5)(9) + 2π(5²)

90π + 50π

140π

5 0

2 years ago

A family purchased tickets for a concert. They paid a total of $90 for 7 adult tickets and 12 child tickets. The price of a chil

andre [41]

A is aldult tickets
b is child tickets

b = 2/3 a

7a + 12b = 90
7a + 12 x 2/3 a = 90
7a + 8a = 90
15a = 90
a = 6; b = 4

4 0

2 years ago

A sqware has an area of 49 sqware feet. A rectangle has an area of 24 sqware feet its lanth is 2 feet longer than its width witc

PSYCHO15rus [73]

Answer:

Step-by-step explanation:

If the square has an area of 49 ft^2, then the length of one of its sides is

s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.

As for the rectangle: let W and L represent the width and length, respectively. Then W*L = 24 ft^2 is the area. L = W + 2 ft. Therefore,

W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0. Thus, W = 4 ft.

The perimeter of this rectangle is P = 2W + 2L, or

P = 2(4 ft) + 2(6 ft) = 24 ft.

The square has the larger perimeter: It is 28 ft.

8 0

3 years ago

A ball weighs 15lb on earth and 5.7 pounds on mars. What is the constant proportionality between weight of an object on mars and

krok68 [10]

So its asking you to find the gravity on earth relative to the gravity on mars.

Set up an equation to figure out the difference between the two gravities

$15x=5.7
\\x=5.7/15$
x=.38

I don't know what constant of proportionality is in this context but a ball on mars would weigh .38 the amount that it does on earth.

5 0

3 years ago

7a/3a+3-5/4a-4=3a/2a+2

jekas [21]

I guess i would be a=2.790220576310317 or −1.2902205763103165

4 0

2 years ago