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Fed [463]
3 years ago
9

100 POINTS!! MICROSOFT EXCEL

Mathematics
2 answers:
aksik [14]3 years ago
7 0

Answer:

See the attached, it should explain everything

murzikaleks [220]3 years ago
4 0

Step-by-step explanation:

A new coffee shop is being built. Its location is the reflection of the arcade's coordinates across

the y-axis. Which procedure will find the correct distance between the arcade and the new coffee shop

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the expression 0.005* 0.85 represents the number of grams of iron in a liquid. how many grams of iron are in the liquid?
gayaneshka [121]
There is a total of  0.00425 grams of iron in the liquid.
7 0
3 years ago
Question<br> Solve: a + 294 = -305.<br> Provide your answer below:
Pepsi [2]

A = -599 if I read the question correctly

6 0
3 years ago
Read 2 more answers
Could anyone help me with this?
Vaselesa [24]

Answer:

Here is your answer with solutions.

7 0
2 years ago
There is a bag of marbles that contains 4 blue marbles, 3 red marbles, 2 green marbles, and 1 brown marble. If one was picked at
Semenov [28]

Answer:

2/15

Step-by-step explanation:

P(B,B) = 4/10 x 3/9

= 2/5 x 1/3 or 2/15

7 0
3 years ago
Total world consumption of iron was approximately 900 million tons in 1993. If consumption had increased by 2.5% each year and t
Lilit [14]

Step-by-step explanation:

We can model the annual consumption of iron by the equation

c = 900 million tons x 1.025^n, where

n is the number of years after 1993 and

c is the consumption for that year.

An estimate for the total consumption of iron can now be obtained by integrating this equation with respect to a dummy variable, x from 0 to n.

C = 900*10^6* \int\limits^n_0 {1.025^x} \, dx

This equation simplifies to

C = 900 million tons x (1.025^n - 1) / ln(1.025), where

x is a dummy variable and

C is the total consumption of iron n years after 1993.

Let R be the amount of iron remaining at n years after 1993, so

R = 480 billion tons - C

R = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

We need to find the value of n when R is 0, so

0 = 480 billion tons - 900 million tons x (1.025^n - 1) / ln(1.025)

Simplify this equation to obtain

n = 107.4

So the iron will run out in the year 1993 + 107 = 2100

6 0
3 years ago
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