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3 years ago

I need help on doing the equal values method. Please tell me how to do y=11-2x y=x+2

Mathematics

1 answer:

noname [10]3 years ago

8 0

Answer:

11-2x=x+2

-3x=9

x=-3

Step-by-step explanation:

y=11-2x

y=x+2

So we use the first equation to plug in for the second equation.

Then we solve for x and get the answer. Hope this helps. Thank you.

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Suppose you have a pocketful of change. You have some pennies (p) and some quarters (q). One expression could be used to describ

faltersainse [42]

Answer:

1.57

Step-by-step explanation:

So we have two equations regarding the number of quarters q and the number of pennies p:

$p+q$

Which represents the total amount of coins and

$0.01p+0.25q$

Which represents the total amount of money in dollars.

So we are asked to evaluation each expression for the situation in which we have 6 quarters and 7 pennies. Thus, plug 6 in for q and 7 in for p:

$p+q\\(7)+(6)=13$

This tells us that we have 16 coins in total.

$0.01(7)+0.25(6)\\=0.07+1.50\\=1.57$

This tells us that we have a total amount of $1.57.

5 0

3 years ago

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The diagram shows a regular dodecagon.Work out the size of one interior angle

nikdorinn [45]

Answer:

150°

Step-by-step explanation:

number of terms=12

sum of exterior angles=360

one exterior angle=360/12=30

interior angle=180-30=150°

5 0

3 years ago

Thaddeus already has $5 saved. He wants to save more to buy a book . Complete the table , and graph the ordered pairs on the coo

Fed [463]

We are going to need to see the table

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4 years ago

The coordinates of three points in the plane are given below. What is the point of the line through B and C?

Keith_Richards [23]

Step-by-step explanation:

y= x +2

.is the equation of line pass through B, C

3 0

3 years ago

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2 tan 30° II 1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago