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3 years ago

9

5. Write an equation for at least one line perpendicular to the line with eachequation.c. 19x

1 answer:

tiny-mole [99]3 years ago

7 0

The first thing you always do with equations like these is get the y alone by moving everything to the other side. Once this is done, you take the opposite reciprocal of the slope. For example, number a, when you have y alone, is y=-1x+2. So the opposite reciprocal of the slope would be just 1, so the resulting equations would be y=1x+2.

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A student takes an exam containing 1414 multiple choice questions. The probability of choosing a correct answer by knowledgeable

Readme [11.4K]

Answer:

0.0082 = 0.82% probability that he will pass

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the students guesses the correct answer, or he guesses the wrong answer. The probability of guessing the correct answer for a question is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 14, p = 0.3$ .

If the student makes knowledgeable guesses, what is the probability that he will pass?

He needs to guess at least 9 answers correctly. So

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 9) = C_{14,9}.(0.3)^{9}.(0.7)^{5} = 0.0066$

$P(X = 10) = C_{14,10}.(0.3)^{10}.(0.7)^{4} = 0.0014$

$P(X = 11) = C_{14,11}.(0.3)^{11}.(0.7)^{3} = 0.0002$

$P(X = 12) = C_{14,12}.(0.3)^{12}.(0.7)^{2} = 0.000024$

$P(X = 13) = C_{14,13}.(0.3)^{13}.(0.7)^{1} = 0.000002$

$P(X = 14) = C_{14,14}.(0.3)^{14}.(0.7)^{0} \cong 0$

$P(X \geq 9) = P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.0066 + 0.0014 + 0.0002 + 0.000024 + 0.000002 = 0.0082$

0.0082 = 0.82% probability that he will pass

6 0

3 years ago

Mean mode median range

jenyasd209 [6]

Exactly, I'm so confused

5 0

3 years ago

A dilation with a scale factor of 2 is applied to the three line segments shown. The resulting images are P′Q′¯¯¯¯¯¯¯, A′B′¯¯¯¯¯

ivanzaharov [21]

Answer:

Step-by-step explanation:

Formula to determine the scale factor,

Scale factor = $\frac{\text{Dimension of the image}}{\text{Dimension of the original}}$

2 = $\frac{P'Q'}{PQ}$

2 = $\frac{P'Q'}{2}$

P'Q' = 4 cm

Similarly, for the length of A'B',

2 = $\frac{A'B'}{AB}$

2 = $\frac{A'B'}{1.5}$

A'B' = 3 cm

For the length of M'N',

2 = $\frac{M'N'}{MN}$

2 = $\frac{M'N'}{3}$

M'N' = 6 cm

4 0

3 years ago

Please help me please help me please help me please help me please help me please help me please

Serga [27]

Answer:

first one is square root

don't know the second tho

4 0

2 years ago

The dance committee of pine bluff school earns$72 from a bake sale and will earn $4 for each ticket they sell to the spring flin

Masja [62]

I think it would be 72+4x=400
400-72= 328
328/4= 82
So the answer would be 82=x

8 0

2 years ago