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borishaifa [10]
3 years ago
7

Gloria and Matt belong to a family structure where they can provide their children with a higher standard of living, but this ma

y prevent them from sharing adequate time with their children. Which type of family are they most likely to belong to?
A)grandparent family
B)dual-employed marriage
C)adoptive family
D)blended family
Computers and Technology
2 answers:
Oksana_A [137]3 years ago
7 0
The answer would be adoptive family.
Oksana_A [137]3 years ago
5 0

Answer:

Dual-employed marriage ( B )

Explanation:

A dual-employed marriage is a type of marriage whereby both partners are employed and this will enable them provide their children with a higher standard of living.

The disadvantage of dual-employed marriage is that the parents won't have quality time to share with their children while the advantage of this kind of marriage is that the family would have access to sufficient finances and hence their standard of living would improve very well .

A grandparent family is a type of family with children and grandparents no parents are available while an adoptive marriage is a type of marriage that involves an adopted child or at least an adopted parent. a blended family involves children from the previous relationships of the parents.

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Answer:

C++ code explained below

Explanation:

#include<bits/stdc++.h>

#include <iostream>

using namespace std;

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{

int max=n+1;

int F[max];

F[0]=0;F[1]=1;

for(int i=2;i<=n;i++)

{

F[i]=F[i-1]+F[i-2];

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int FiboR(int n)

{

if(n==0||n==1)

return n;

else

return (FiboR(n-1)+FiboR(n-2));

}

int main()

{

long long int i,f;

double t1,t2;

int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};

cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;

cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;

for(i=0;i<16;i++)

{

clock_t begin = clock();

f=FiboR(n[i]);

clock_t end = clock();

t1=double(end-begin); // elapsed time in milli secons

begin = clock();

f=FiboNR(n[i]);

end = clock();

t2=double(end-begin);

cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds

}

return 0;

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Answer:

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Explanation:

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Answer:

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If short time memories is not rehearsed, they don't last and are easily forgotten, they actually last for about 20-30 seconds.

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