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vovangra [49]
3 years ago
15

The parallelogram has a base of 8 cm and corresponding height of 4 cm. The parallelogram is changed proportionally and is dilate

d by a scale factor of ½. What is the area of the new reduced parallelogram after the dilation occurs?
Mathematics
1 answer:
sukhopar [10]3 years ago
8 0

Answer:

The area of the new reduced parallelogram after dilation is 8 cm^2

Step-by-step explanation:

Mathematically, the area of a parallelogram = b * h

before dilation, area of the parallelogram = 8 * 4 = 32 cm^2

After dilation by a factor of 1/2, the base of the parallelogram becomes 1/2 * 8 = 4cm while the height becomes 1/2 * 4 = 2cm

Thus, the area of the dilated parallelogram is 4 * 2 = 8 cm^2

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If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

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