Answer:
a) I = √ (2G m³ (1/2r³ - 1/R)), b) I = √ (8 G m³ (1/2r -1/R))
Explanation:
.a) The relation of the Impulse and the moment is
I = Δp = m - m v₀
We can use Newton's second law with force the force of universal attraction
F = ma
G m m / r² = m a
dv / dt = G m / r²
Suppose re the direction where the spheres move is x
dv/dx dx/dt = G m / x²
dv/dx v = G m / x²
v dv = G m dx / x²
We integrate
v² / 2 = Gm (-1 / x)
We evaluate this integra from the lower limit v = 0 for x = R to the upper limit, where the spheres v = v and x = 2r are touched
v² / 2-0 = G M (-1 / R + 1 / 2r)
v = √ [2Gm (1 /2r - 1/ R) ]
The impulse on the sphere is
I = m vf - m v₀
I = m vf - 0
I = m √ (2Gm (1 / 2r-1 / R)
I = √ (2G m³ (1/2r³ - 1/R))
b) during the crash each sphere arrives with a velocity v and leaves with a velocity –v, the same magnitude but opposite direction
I = m - m v₀
I = m v - m (-v)
I = 2mv
I = 2m √ (2Gm (1 / 2r-1 / R)
I = √ (8 G m³ (1/2r -1/R))
Answer:
Part a)
Part b)
Explanation:
Part a)
Energy delivered to the building is given as
Work done by the electricity is given as
so we have
Part b)
As we know that water in and out temperature is given as
so we have
The answer to this question is C. Lakes of hydrocarbons. Trust me this is the answer before i got the results i thought it was lakes of mercury.
Answer:
i think it would be Galvanometer
Explanation:
because it would have to be a type of coil or wire