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aev [14]
3 years ago
6

Which would you use with a circuit to determine if a magnet was moving in close proximity to the circuit?

Physics
2 answers:
stealth61 [152]3 years ago
7 0

Answer:

i think it would be Galvanometer

Explanation:

because it would have to be a type of coil or wire

Volgvan3 years ago
4 0
I believe the right answer is galvanometer
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A boy throws a ball up into the air with a speed of 8.2 m/s. The ball has a mass of 0.3 kg. How much gravitational potential ene
diamong [38]
We can use the law of conservation of energy to solve the problem.

The total mechanical energy of the system at any moment of the motion is:
E=U+K = mgh + \frac{1}{2}mv^2
where U is the potential energy and K the kinetic energy.

At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:
E_i = K_i =  \frac{1}{2}mv^2 =  \frac{1}{2}(0.3 kg)(8.2 m/s)^2=10.09 J

When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:
E_f = U_f
But the mechanical energy must be conserved, Ef=Ei, so we have
U_f = K_i
and so, the potential energy at the top of the flight is
U_f = K_i = 10.09 J
7 0
3 years ago
Read 2 more answers
A ball is droped from a height of 16m how much time will pass before the ball hits the ground​
sergey [27]

Answer:

The time is 1.8s

Explanation:

The ball droped, will freely fall under gravity.

Hence we use free fall formula to calculate the time by the ball to hit the ground

h= \frac{1}{2}g{t}^{2}

Where h is the height from which the ball is droped, g is the acceleration due to gravity that acted on the ball, and t is the time taken by the ball to hit the ground.

From the question,

h=16m

Also, let take

g = 9.8m{s}^{-2}

By substitution we obtain,

16= \frac{1}{2}\times 9.8{t}^{2}

\implies32=9.8{t}^{2}

Diving through by 9.8

\frac{32}{9.8}= \frac{ 9.8{t}^{2} }{9.8}

\implies{t}^{2} =3.265

square root both sides, we obtain

\implies t= \sqrt{3.265}

t=1.8s

4 0
3 years ago
A small mailbag is released from a helicopter that is descending steadily at 2.52 m/s. (a) After 4.00 s, what is the speed of th
gogolik [260]

Answer: 41.72m/s

Explanation: v= u + gt

V = 2.52 + 9.8(4.00)

V = 41.72m/s

6 0
2 years ago
Which phrase best describes sir isaac newton's contributions to modern science and therefore to the industrial revolution?
astraxan [27]
Can you please give the phrases? 

But, I'll help what I can.

First, he was the first to discover gravity. He was not bonked by the head by an apple, rather he watched an apple fall from a tree before he decided to explore gravity further. 

He was also the first scientist to be knighted, which is a great honor, as you can expect. 

Newton also developed The Three Laws of Motion. They are extremely important to physics and are considered some of the foundation for physics today. 

He also discovered calculus, which is complex math that is very helpful to scientists today. 

He also discovered the color spectrum using a glass prism, a dark room and window shade with a hole in it. He was able to project the color spectrum onto a piece of paper.

Those are the few I can think of now, but hope it helps!


7 0
3 years ago
Small rockets are used to make small adjustments in the speed of satellites. One such rocket has a thrust of 42 N. If it is fire
Over [174]

To solve this problem we will apply the concepts related to Newton's second law that relates force as the product between acceleration and mass. From there, we will get the acceleration. Finally, through the cinematic equations of motion we will find the time required by the object.

If the Force (F) is 42N on an object of mass (m) of 83000kg we have that the acceleration would be by Newton's second law.

F = ma \rightarrow a = \frac{F}{m}

Replacing,

a =\frac{42N}{83000kg}

a =5.06*10^{-4}m/s^2

The total speed change

\Delta v = v_f -v_0 \rightarrow v_f =\text{Final velocity and } v_0 = \text{Initial velocity } we have that the value is 0.71m/s

If we know that acceleration is the change of speed in a fraction of time,

a= \frac{\Delta v}{t} \rightarrow t = \frac{\Delta v}{a}

We have that,

t= \frac{0.71m/s}{5.06*10^{-4}m/s^2 }

t = 1403.16s

Therefore the Rocket should be fired around to 1403.16s

7 0
3 years ago
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