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Sauron [17]
3 years ago
9

HELP PLEASE URGENT NEED TO PASS THIS CLASS

Mathematics
2 answers:
lana [24]3 years ago
5 0
Hello!

Answer is y = 1/3x - 1
ella [17]3 years ago
5 0
B = -1
m = rise/run = 1/4

y = 1/4 x + 1
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Easy 10 points and brainliest :)
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quadrant 1

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both of them are positive

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Suppose that f(x) = x2 and g(x) = 2/5 x2. Which statement best compares the
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b or d

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Let g(x) = -x2 + x. Find g(-10).
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Question 10
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a.(-b) ( third choice)

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3 years ago
Outside temperature over a day can be modelled as a sinusoidal function. Suppose you know the high temperature for the day is 10
WINSTONCH [101]

Answer:

The function for the outside temperature is represented by T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right], where t is measured in hours.

Step-by-step explanation:

Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:

Amplitude

A = \frac{100\º-70\º}{2}

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Mean temperature

\bar T = \frac{70\º+100\º}{2}

\bar T = 85\º

Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:

T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]

Where:

\bar T - Mean temperature, measured in degrees.

A - Amplitude, measured in degrees.

\tau - Daily period, measured in hours.

t - Time, measured in hours. (where t = 0 corresponds with 5 AM).

If \bar T = 85\º, A = 15\º and \tau = 24\,h, the resulting function for the outside temperature is:

T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]

3 0
3 years ago
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