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kotykmax [81]
4 years ago
9

Is the amount 0.31 more less or equal to half.

Mathematics
1 answer:
Fudgin [204]4 years ago
8 0
If you mean half as in 1/2, then yes, 0.31 is less than half because 1/2 as a decimal is 0.50. 

Make me brainliest answer if this helped you!
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(i need this ASAP)
kondor19780726 [428]

Answer:

A

Step-by-step explanation:

is there a need for explanation

3 0
3 years ago
A bank manager wants to encourage new customers to open accounts with principals of at least ​$2 comma 500. He decides to make a
prisoha [69]

Answer:

To earn $10 in 1st month, the principal must be $4,000.

No, the poster cannot claim that "Open an account of ​$2 comma 500 and earn at least ​$10 interest in 1​ month!".

Step-by-step explanation:

We have been given that a bank manager wants to encourage new customers to open accounts with principals of at least ​$2,500. He decides to make a poster advertising a simple interest rate of 3​%. We are asked to find the principal to advertise that one can earn ​$10 the first​ month.

We will use simple interest formula to solve our given problem.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

r=3\%=\frac{3}{100}=0.03

1 month will be equal to \frac{1}{12}.

\$10=P\cdot0.03\cdot \frac{1}{12}

\$10=0.0025P

\frac{\$10}{0.0025}=\frac{0.0025P}{0.0025}

P=\$4000

Therefore, to earn $10 in 1st month, the principal must be $4,000.

Now, we will check if an account of ​$2,500 can earn at least ​$10 interest in 1​ month.

I=\$2500\cdot 0.03\cdot \frac{1}{12}

I=\$6.25

Since the account earns an amount of $6.25 in one month, therefore, the poster is not true.

4 0
3 years ago
Write 5.9/100 as a percent
leonid [27]
Here is your answer:

<span>5.9/100 * 100 = 0.059
0.059 * 100 = 5.9%
=5.9% 

Therefore the answer is "5.9%."

Hope this helps!</span>
5 0
4 years ago
How much of a 60% saline solution would you need to add to pure water to create 10 L of a 50% saline solution ?
Julli [10]
So say, we add "x" of the 60% saline solution, now, how much salt is in that solution?  now 60% is salt but the rest is something else, but only salt is 60% of "x", or (60/100) * x, or 0.6x.

likewise, for the 10 Liters, if only 50% is salt, then is just (50/100) * 10 or 5.

now... let's check the water whilst we add "y" amount, the water has no salt at all, freshwater for that matter, so, salinity is 0%.  or (0/100) * y or 0.

\bf \begin{array}{lccclll}&#10;&\stackrel{liters}{amount}&\stackrel{\textit{\% of salt}}{quantity}&\stackrel{\textit{total salt}}{quantity}\\&#10;&------&------&------\\&#10;\textit{60\% sol'n}&x&0.60&0.6x\\&#10;\textit{pure water}&y&0.00&0y\\&#10;------&------&------&------\\&#10;mixture&10&0.50&5&#10;\end{array}

\bf \begin{cases}&#10;x+y=10\\&#10;0.6x+0y=5&#10;\end{cases}&#10;\\\\\\&#10;0.6x=5\implies x=\cfrac{5}{0.6}\implies x=\cfrac{25}{3}\implies x=8\frac{1}{3}
7 0
3 years ago
Please Help Asap. Very Hard.
Genrish500 [490]

According to the plot, when t=0,

y_1(0)=a_1\sin0=0

y_2(0)=a_2\cos0=a_2

a_1 and a_2 are the amplitudes of the waves y_1 and y_2, respectively. From the plot it's clear that both a_1 and a_2 are positive, but the maximum value of y_2 is evidently smaller than the maximum value of y_1. So 0, making the answer B.

4 0
3 years ago
Read 2 more answers
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