To know the electrostatic force between two charges or between two ions, you can use the Coulomb's Law. The equation is F = k*q1*q1/r^2, where F is the electrostatic force, q1 and q2 are the charger for Na and Cl, and r is the distance between the centers of both atoms. In literature, the distance is 0.5 nm or 0.5 x 10^-9 meters. The charge for Na+ and Cl- is the same magnitude but different in sign. Since Na+ is a cation, its charge is +1.603x10^-19 C (the charge of an electron). For Cl- being an anion, its charge is -1.603x10^-19 C. The constant k is an empirical value equal to 9x10^9. Using the formula:
F = (9x10^9)(+1.603x10^-19)(-1.603x10^-19)/(0.5 x 10^-9)^2
F = -9.25 x 10^-10 Newtons
The negative denotes that the net force is more towards the Cl- ion.
The density of gold is 19.3 g/cm³
Ag= silver
Au= gold.
density (Ag)=10.5 g/cm³.
density (Au)=19.3 g/cm³
We have to calculate the mass of 5 cm³ silver:
10.5 g---------------------1 cm³
x--------------------------- 5 cm³
x=(10.5 g * 5 cm³) / 1cm³ ≈52.5 g
And we have to calculate the mass of 5 g gold.
19.3 g------------------------1 cm³
x-------------------------------5 cm³
x=(19.3 g * 5 cm³) / 1cm³≈96.5 g
Then 5 cm³ silver are 52.5 g of mass, and 5 cm³ gold are 96.5 g of mass, therefore, gold would have a greater mass than silver.
answer:5 cm³ gold would have a greater mass than 5 cm³ silver.
Answer : The correct option is "record 10.00 ml in the notebook after using it."
Explanation :
If an instrument has "10 mL TD" written on it, that means the instrument is meant To Deliver (TD) 10 mL of volume.
Therefore the option that has 5.00 mL is not correct.
"+/- 0.01 mL" indicates the precision of the instrument. We know that no measurement is 100% accurate and there is always some uncertainty associated with any measurement.
Here, 0.01 indicates the uncertainty in the measurement.
When we have 0.01 mL , that means the instrument can record precisely to the hundredths place.
The more the significant figures, the greater is the accuracy of the measurement.
Therefore when we use an instrument that has "+/- 0.01 mL" written on it, we should record the reading as 10.00 mL
Saturated solution is when a solution has dissolved as much as it can
The mass of the empty flask is 17.4916 g. Now after feeling the ordinary water the mass of the flask is 43.9616 g. Thus the change of weight due to addition of ordinary water is (43.9616 - 17.4916) = 26.47 g.
Now as the density of the ordinary water at 20°C is 0.9982 g/ml, so 26.47 g is equivalent to 
mL of water. Thus the capacity of the flask is 26.5177 mL.
Now the density of heavy water is 1.1053 g/mL at 20°C. Thus 26.5177 mL of heavy water is equivalent to (1.1053×26.5177) = 29.310 g.
Thus the total weight of the flask filled with heavy water will be (17.4916 + 29.310) = 46.8016 g at 20°C.
