Answer:
P = 2.65 E-3 mm Hg
Explanation:
liquid-vapor equilibrium:
⇒ ec. Clausius-Clapeyron:
- Ln (P2/P1) = - ΔHv/R [ (1/T2) - (1/T1) ]
∴ R = 8.314 E-3 KJ/K.mol
∴ ΔHv = 59.11 KJ/mol
∴ T2 = 25°C ≅ 298 K
∴ T1 = 356.7°C = 629.7 K
normal boiling point:
∴ P = 1 atm = P1 = 101.325 KPa
vapor pressure (P2):
⇒ Ln P2 - Ln (101.325) = - (59.11 KJ/mol)/(8.314 E-3 KJ/K.mol)*[ (1/298) - (1/629.7) ]
⇒ Ln P2 - 4.618 = - (7109.694 K)*[ 1.7676 E-3 K-1 ]
⇒ Ln P2 = 4.618 - 12.567
⇒ P2 = e∧(-7.9494)
⇒ P2 = (3.5313 E-4 KPa)×(7.50062mm Hg/KPa) = 2.65 E-3 mm Hg
In any compound there are two types of ions are present, cations and anions. Cations are positively charged ions and formed by losing electrons and anions are formed by gaining electrons and are negatively charged ions.
So, in K₂HPO₄, there are positive charged and negative charged ions are present. so there is K⁺ ion and HPO₄⁻² ion is present in K₂HPO₄
C.they conduct an electric current in solution
Answer:
anything that is aqueous cannot be separated with filter paper.
you've got table salt, glucose, and carbon dioxide which are all soluble in water.
SiO2 is quartz (sand) which is not soluble, and will be easily filtered out.