The following chemical reaction will occur:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
Explanation:
Because the bromide (Br₂) have a higher reactivity than iodide (I₂) it is able the remove the iodide from its salts. So the bromide will react with sodium iodine (NaI) to produce sodium bromide (NaBr) and iodine.
The chemical reaction is:
Br₂ (l) + 2 NaI (s) → 2 NaBr (s) + I₂ (s)
where:
(l) - liquid
(s) - solid
Learn more about:
balancing chemical equations
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PUMICE<span>: An </span>igneous<span>-volcanic rock, it is a porous, brittle variety of rhyolite and is light enough to float. It is formed when magma of </span>granite<span> composition erupts at the earth's surface or intrudes the crust at shallow depths. It is used as an abrasive material in hand soaps, emery boards, etc.</span>
We know that the particles in a matter have energy. They have kinetic energy, potential energy, chemical energy, electrical energy etc.
When we give heat to a matter it gains energy and there is an increase in its internal energy. Or we can say that particles in a matter have more energy at higher temperature than particles in a matter at low temperature
As ice is formed below zero degree celsius so the particles in ice must have lesser energy than water at higher temperature.
Thus true statement will be
The particles in boiling water have more energy than the particles in ice water do.
Mass O2 = = 16.832 g
<h3>Further explanation</h3>
Given
43 grams of potassium chlorate
Required
Mass of O2
Solution
Reaction
2KClO3 ⇒3O2 + 2KCl
Mol KClO3 :
= mass : MW
= 43 g : 122,55 g/mol
= 0.3509
From the equation, mol O2 :
= 3/2 x moles KClO3
= 3/2 x 0.3509
= 0.526
Mass O2 :
= 0.526 x 32 g/mol
= 16.832 g
Answer:
The answer to your question is ΔHrxn = 0 kJ
Explanation:
Process
1.- Multiply Equation 1 by 2
2C(coal) + 2H₂O ⇒ 2CO (g) + 2H₂ ΔH rxn = 259.4 kJ
2.- Sum equation 2
CO(g) + H₂O ⇒ CO₂ (g) + H₂ (g) ΔHrxn = -41 kJ
Result
2C + 3H₂O + CO ⇒ 2CO + 3H₂ + CO₂ ΔHrxn = 218.4 kJ
Simplification
2C + 3H₂O ⇒ CO + 3H₂ + CO₂
3.- Sum equation 3
CO(g) + 3H₂ (g) ⇒ CH₄ (g) + H₂O (g) ΔHrxn = -218.4 kJ
Result
2C + 3H₂O + 3H₂ + CO ⇒ CO + 3H₂ + CO₂ + CH₄ + H₂O
Simplification
2C + 2H₂O ⇒ CO₂ + CH₄ ΔHrxn = 0 kJ
