How can the distributive property be used to find 4 x 875? draw an array.

Surveys conducted in American high schools concluded that 90% of the students in a sample of 400 students had more than one acti

kenny6666 [7]

The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to

SE = sqrt(p*q/n) where p is the population proportion q is 1-p, and n is the sample size.

(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.) 

The margin of error will be Zc*SE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error.

For a 90% confidence interval, Zc is 1.645.

So the margin of error is 1.645 * sqrt(.9*.1/400), roughly .025. So your confidence interval would be around [.875, .925]

The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.

4 0

3 years ago

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How do you solve this btw it’s gr11 applied

Georgia [21]

Answer:62

Step-by-step explanation: 62

3 0

3 years ago

Kryptonite is a material found on the planet Krypton and has various effects, most importantly on Superman. The most common type

Rashid [163]

Answer:

The maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

Step-by-step explanation:

dy/dt = y(1/t - k)

separating the variables, we have

dy/y = (1/t - k)dt

dy/y = dt/t - kdt

integrating both sides, we have

∫dy/y = ∫dt/t - ∫kdt

㏑y = ㏑t - kt + C

㏑y - ㏑t = -kt + C

㏑(y/t) = -kt + C

taking exponents of both sides, we have

$\frac{y}{t} = e^{-kt + C} \\\frac{y}{t} = e^{-kt}e^{C} \\\frac{y}{t} = Ae^{-kt} (A = e^{C})\\y = Ate^{-kt}$

when t = 1 hour, y = 15 grams. So,

$y = Ate^{-kt}\\15 = A(1)e^{-kX1}\\15 = Ae^{-k}$ (1)

when t = 3 hours, y = 30 grams. So,

$y = Ate^{-kt}\\30 = A(3)e^{-kX3}\\30 = 3Ae^{-3k}$ (2)

dividing (2) by (1), we have

$\frac{30}{15} = \frac{3Ae^{-3k}}{Ae^{-k}} \\2 = 3e^{-2k}\\\frac{2}{3} = e^{-2k}$

taking natural logarithm of both sides, we have

-2k = ㏑(2/3)

-2k = -0.4055

k = -0.4055/-2

k = 0.203

From (1)

$A = 15e^{k} \\A = 15e^{0.203} \\A = 15 X 1.225\\A = 18.36$

Substituting A and k into y, we have

$y = 18.36te^{-0.203t}$

The maximum value of y is obtained when dy/dt = 0

dy/dt = y(1/t - k) = 0

y(1/t - k) = 0

Since y ≠ 0, (1/t - k) = 0.

So, 1/t = k

t = 1/k

So, the maximum value of y is obtained when t = 1/k = 1/0.203 = 4.93 hours

$y = 18.36(1/0.203)e^{-0.203t}\\y = \frac{18.36}{0.203}e^{-0.203X1/0.203}\\y = 90.44e^{-1}\\y = 90.44 X 0.3679\\y = 33.27 g$

So the maximum amount of red kryptonite present is 33.27 g after 4.93 hours.

3 0

3 years ago

Max and Ben both collect baseball cards. Ben has more baseball cards than Max. The number of baseball cards Max has is m, and th

Temka [501]

Answer:

A) m + 1 < b + 1

Step-by-step explanation:

3 0

3 years ago

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3/4 of 24 is 3 groups of 6, which is 18. So Han ate 18 less than Tyler, or Han at 6. So you take the 24(x) and you subtract 24 o

aksik [14]

Answer:

Step-by-step explanation:

Let the total amount ate by Tyler and Han be 24

Let the amount Tyler ate be x

Amount Han ate be y

If Tyler ate 3/4 of the total, then Amount ate by Tyler is expressed as;

x = 3/4of 24

x = 3/4×24

x = 3×6

x = 3(6)

x = 18

Hence the amount Tyler ate is 18

If Han ate 18 less than Tyler, the amount ate by Han will be;

Han y = 24-(3/4(24)

y = 24-{3(6)}

y = 24-18

y = 6

Hence the total Han ate is 6

8 0

3 years ago