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MA_775_DIABLO [31]
3 years ago
15

⅔ = 8⁄₁₂ Yes or No? Are they Equivalent?

Mathematics
2 answers:
tester [92]3 years ago
8 0

Answer:

yes

x 4 you have the time set by 4 to get the 12s a denominator and three is the same as 12 so they can add up so 8 plus to so intimate 2 * 8 but equal your answer

Y_Kistochka [10]3 years ago
3 0

Step-by-step explanation:

\frac{2}{3} \times  \frac{4}{4}  =  \frac{8}{12}

yes

............

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gizmo_the_mogwai [7]

Answer:

4

Step-by-step explanation:

on edg

5 0
3 years ago
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The sum of a number times 3 and 7 equals 2
ella [17]
3 x + 7 = 2 
3 x = 2 - 7
3 x = - 5
x = - 5/3 

3 ( -5/3) + 7  = - 15/3 + 7 = - 5 + 7 = 2 
7 0
3 years ago
What is the mean absolute deviation of the data set
Ludmilka [50]

Answer:

Mean absolute deviation. The mean absolute deviation of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset

Step-by-step explanation:

Hope this helps

7 0
3 years ago
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Value expression 0.5*2
topjm [15]
0.5*2=1


Explanation: 0.5+0.5 =1
4 0
3 years ago
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A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students
xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample  size n_1 = 178

the sample size n_2 = 226

the sample mean \overline x_1 = 54.4

the sample mean \overline x_2 = 74.5

population standard deviation \sigma_1 = 18.58

population standard deviation \sigma_2 = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005} is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}

1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}

1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}

1.645 \times\sqrt{2.34042}

\simeq 2.52

The lower limit = ( \overline x_1 - \overline x_2) - (M.O.E)

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = ( \overline x_1 - \overline x_2) + (M.O.E)

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0
3 years ago
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