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2 years ago

3(d-8)-5=9(d+2)+1 need help

Mathematics

1 answer:

nika2105 [10]2 years ago

5 0

Answer:

d=-8

Step-by-step explanation:

1) Use the Distributive property on the left side of the equation:

3d-24-5=9(d+2)+1

2) Use the Distributive property on the right side of the equation:

3d-24-5=9d+18+1

3) Combine alike terms:

3d-29=9d+19

4) add a 29 to both sides:

3d=9d+48

5) Subtract a 9d from both sides:

-6d=48

6) Divide both sides by -6:

d=-8

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3 years ago

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Step-by-step explanation:

For each pen, there are only two possible outcomes. Either it is defective, or it is not. The probability of a pen being defective is independent from other pens. So we use the binomial probability distribution to solve this question.

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The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

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(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective. (Use 3 decimal places.)

This is $P(X \leq 2)$ when $p = 0.1$ . So

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{17,0}.(0.1)^{0}.(0.9)^{17} = 0.167$

$P(X = 1) = C_{17,1}.(0.1)^{1}.(0.9)^{16} = 0.315$

$P(X = 2) = C_{17,2}.(0.1)^{2}.(0.9)^{15} = 0.280$

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.167 + 0.315 + 0.280 = 0.762$

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