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Alex_Xolod [135]
3 years ago
14

Which travels at a greater speed, visible or infrared light?

Physics
1 answer:
Ksju [112]3 years ago
7 0
Infrared light because it is barely able to be seen
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Give two quantitative observation george might record
Over [174]
There are four chipmunks on that tree

two of the dogs have white fur
8 0
3 years ago
Set up the Applied Force (force exerted) on both crates with the current Friction setting at 350 N. On Part 2, draw a force diag
ryzh [129]

The acceleration will be constantly equal to 1 m/s².Option c is correct.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 350 N

Friction force,f=350 N

F=f

Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².

Hence option c is correct.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

3 0
2 years ago
As a bicycle pump inflates a tyre, it pressure rises from 30 kPa to 40 kPa at constant temperature of 30 °C. By assuming the air
MArishka [77]

This question involves the concepts of work done, pressure, and temperature.

The work done per mol of the air is "-724.71 J/mol".

Using the given formula for work done:

W=RTln\frac{P_1}{P_2}

where,

W = work done per mol = ?

R = universal gas constant = 8.314 J/mol.k

T = absolute temperature = 30°C + 273 = 303 k

P₁ = initial pressure = 30 KPa

P₂ = final pressure = 40 KPa

Therefore,

W= (8.314\ J/mol.k)(303\ k)ln\frac{30\ KPa}{40\ KPa}\\

<u>W = -724.71 J/mol</u>

<u></u>

Learn more about pressure here:

brainly.com/question/23358029?referrer=searchResults

7 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
Once ignited, a small rocket motor on a spacecraft exerts a constant force of 10 N for 7.80s. During the burn the rocket causes
Marat540 [252]

Answer:

a = 0.01 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which says that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = forces = 10 [N]

m = mass = 100 [kg]

a = acceleration [m/s²]

10 = 100*a

a = 0.01 [m/s²]

4 0
3 years ago
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