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wlad13 [49]
2 years ago
13

Set up the Applied Force (force exerted) on both crates with the current Friction setting at 350 N. On Part 2, draw a force diag

ram that includes all external forces acting on the two crates
Physics
1 answer:
ryzh [129]2 years ago
3 0

The acceleration will be constantly equal to 1 m/s².Option c is correct.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

Given data;

Force,F = 350 N

Friction force,f=350 N

F=f

Because the frictional and applied forces on the two boxes are of equal strength, both move at the same pace. As a result, the acceleration will be constantly equal to 1 m/s².

Hence option c is correct.

To learn more about the force refer to the link;

brainly.com/question/26115859#SPJ1

#SPJ1

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If a wave y(x, t) (6.0 mm) sin(kx (600 rad/s)t f) travels along a string, how much time does any given point on the string take
kipiarov [429]

Answer:

t₁ - t₂ = 0.0011 s

Explanation:

given,

y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

now,

y m = 6 mm        ω = 600 rad/s

y₁ = + 2.0 mm    y₂ = -2 .0 mm

now,

2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)

so,

kx + (600 rad/s)t₁ + Φ = \dfrac{\pi}{180}sin^{-1}(\dfrac{1}{3})......(1)

we have multiplied with π/180 to convert angle into radians

kx + (600 rad/s)t₂ + Φ = \dfrac{\pi}{180}sin^{-1}(-\dfrac{1}{3})......(2)

subtracting both the equation (1)-(2)

600(t₁-t₂) =  \dfrac{2\pi}{180}sin^{-1}(\dfrac{1}{3})

now,

    t₁ - t₂ = 0.0011 s

time does any given point on the string take to move between displacements is equal to 0.0011 s

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Which is not a step in the scientific method?
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Question 7
VLD [36.1K]

Answer: m= 4kg

Explanation:

Use equation for force:

F=m*a

F=20 N

a=5 m/s²

m=?

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---------

F=m*a

m=F/a

m=(20 kg*m/s²)/5m/s²

m=4kg

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