Question

A jet lands on an aircraft carrier at 140 mi/h. What is its acceleration if it stops in 2.0 seconds?

Answer 1

Answer:

Acceleration, $a=-31.29\ m/s^2$

Explanation:

It is given that,

Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{0-62.58}{2}$

$a=-31.29\ m/s^2$

So, the acceleration of the aircraft is $31.29\ m/s^2$ and the car is decelerating. Hence, this is the required solution.