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liq [111]
3 years ago
9

A jet lands on an aircraft carrier at 140 mi/h. What is its acceleration if it stops in 2.0 seconds?

Physics
1 answer:
sergejj [24]3 years ago
4 0

Answer:

Acceleration, a=-31.29\ m/s^2

Explanation:

It is given that,

Initial speed of the aircraft, u = 140 mi/h = 62.58 m/s

Finally, it stops, v = 0

Time taken, t = 2 s

Let a is the acceleration of the aircraft. We know that the rate of change of velocity is called acceleration of the object. It is given by :

a=\dfrac{v-u}{t}

a=\dfrac{0-62.58}{2}

a=-31.29\ m/s^2

So, the acceleration of the aircraft is 31.29\ m/s^2 and the car is decelerating. Hence, this is the required solution.

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Hope this help you!!

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