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2 years ago

1. Find the Length of Line AD A(6, 2) D(-3, -2)

Mathematics

1 answer:

densk [106]2 years ago

8 0

Answer:

Step-by-step explanation:

$\sqrt{(2-(-2))^{2} + (6-(-3))^2}$

= $\sqrt{4^{2} + 3^{2} } \\$

= $\sqrt{25}$

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How to differentiate y=x^n using the first principle. In this question, I cannot use the rule of differentiation. I have to do t

Zarrin [17]

By first principles, the derivative is

$\displaystyle\lim_{h\to0}\frac{(x+h)^n-x^n}h$

Use the binomial theorem to expand the numerator:

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$(x+h)^n=x^n+nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n$

where

$\dbinom nk=\dfrac{n!}{k!(n-k)!}$

The first term is eliminated, and the limit is

$\displaystyle\lim_{h\to0}\frac{nx^{n-1}h+\dfrac{n(n-1)}2x^{n-2}h^2+\cdots+nxh^{n-1}+h^n}h$

A power of $h$ in every term of the numerator cancels with $h$ in the denominator:

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Finally, each term containing $h$ approaches 0 as $h\to0$ , and the derivative is

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3 years ago

Will mark brainlest how to multipy it

Lesechka [4]

Answer:

$\displaystyle x = 2 \sqrt{3}$

Step-by-step explanation:

we would like to solve the following equation:

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in order to do so do cross multiplication:

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divide both sides by √3:

$\displaystyle x = \frac{6}{ \sqrt{3}}$

since we ended up with a square root on the denominator so we can consider rationalising the denominator to do so multiply both numerator and denominator by √3 which yields:

$\displaystyle x = \frac{6}{ \sqrt{3}} \times \frac{ \sqrt{3} }{ \sqrt{ 3} }$

simplify multiplication:

$\displaystyle x = \frac{6 \sqrt{3} }{ 3}$

reduce fraction:

$\displaystyle x = 2 \sqrt{3}$

and we are done!

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n200080 [17]

Assuming it's not a leap year,
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Debora [2.8K]

Answer:

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Step-by-step explanation:

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