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Alekssandra [29.7K]
3 years ago
10

A sample of an unknown compound has a percent composition of 52.14% carbon, 13.13% hydrogen, and 34.73% oxygen. Which compounds

could the sample be?
CH3CH3CH2O2
C2H5OH
C4H10O2
C4H12O2
CH3CH3CH2OOH
Chemistry
2 answers:
tamaranim1 [39]3 years ago
4 0

Answer:

1.elements: carbon. hydrogen. oxygen

2.percentage: 52.14. 13.13. 34.73

3.Number of :

moles, you 4.345. 13.13 2.171

divide the

% with mass

number.

4.mole ratio, : 2 6 1

you divide

with the

list number

of moles

throughout.

5.The formula C2H5OH

of the sample:

Explanation:

Just follow the steps above are well explained ,thank

Iteru [2.4K]3 years ago
3 0

Answer:

C4H12O2

Explanation:

Molar mass of Carbon=12

Molar mass of Hydrogen =1

Molar mass of Oxygen = 16

C H O

52.14/12 13.13/1 34.73/16

4.345/2.17 13.13/2.17 2.17/2.17

2 6 1

C2H6O

(C2H6O)2

C4H12O2

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Answer:

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The IUPAC names of the organic compounds would be as follows:

1. Methanol or 1-Methanol

2. Propan-2-ol or 2-Propanol

3. 2-MethylButane

4. 1-Hexanol

5. 1-Heptanol

<h3>Naming organic compounds</h3>

In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:

  • The longest carbon chain, otherwise known as the parent chain, is considered.
  • The substituents must be identified
  • The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
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Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:

  • Methanol or 1-Methanol
  • Propan-2-ol or 2-Propanol
  • 2-MethylButane
  • 1-Hexanol
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More on IUPAC naming can be found here: brainly.com/question/16631447

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7 0
1 year ago
Which energy change occurs during boiling?
neonofarm [45]
Heat energy is absorbed by the substance.
4 0
3 years ago
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Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is
tankabanditka [31]

Answer:

M_{A} : M_{B}  = 4 : 1

Explanation:

Given that:

Volume of a cylinder = \pir^{2}h

For cylinder A, l_{A} = h_{A} = \frac{1}{4} l_{B} and r_{A} = 4r_{B}.

Volume of cylinder A = \pi(4r_{B}) ^{2} × \frac{1}{4} l_{B}

                                   = 4\pir_{B} ^{2} l_{B}

Volume of cylinder B =  \pi(r_{B}) ^{2} l_{B}

                                  =  \pir_{B} ^{2}l_{B}

To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).

i.e    ρ = \frac{M}{V}

Thus, since the cylinders are made from the same material, they have the same density  (ρ). So that;

density of A = density of B

density of A = \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }

density of B = \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

⇒            \frac{M_{A} }{4\pi r_{B} ^{2}l_{B}    }  =  \frac{M_{B} }{\pi r_{B} ^{2}l_{B}  }

The ratio of mass of cylinder A to that of B is given as;

                       \frac{M_{A} }{M_{B} }  =  \frac{4\pi r_{B} ^{2} l_{B}  }{\pi r_{B} ^{2} l_{B}  }

⇒                        \frac{M_{A} }{M_{B} } = \frac{4}{1}

Therefore, M_{A} : M_{B}  = 4 : 1

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ella [17]

Answer:

D

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It can be used for measuring the volume of a solid indirectly by measuring the displacement of a liquid.

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