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7nadin3 [17]
3 years ago
11

What are the following numbers in scientific notation 0.0006250

Chemistry
1 answer:
wlad13 [49]3 years ago
3 0
First one, 6.250 * 10^(-4). Second one, 9.532 * 10^6. Third one, 4.38904 * 10^5. Forth one, 4.5833 * 10^(-3). The zero before first non-zero number can ignore.
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Why do some atoms form positive ions and others form negative ions?
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It is energetically favorable for all atoms to have a complete outer electron shell. Loosely, the atoms on the left hand side of the periodic table only have a few extra electrons in their outer shell so it is energetically favorable for them to lose them. The atoms on the right hand side of the periodic table almost have enough electrons in their outer shell and so they have a tendency to gain them. Once electrons have left an electron shell, an atom will have a positive charge because it has more protons (positive charges) than electrons (negative charges). Similarly, an electron which has gained electrons to complete its outer shell will have a negative charge because it now has more electrons (negative charge) than protons (positive charge).
8 0
3 years ago
How many atoms are in 2.45 moles of hydrogen
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Answer:

There are 1.4754246675000002e+24 atoms of Hydrogen within the measurement of 2.45 moles of hydrogen!

Explanation:

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3 years ago
One calcium atom for every two iodine atoms chemical formula
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2 years ago
I need help please asap
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8 0
3 years ago
The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the limiti
nadezda [96]

Answer:

The limiting reactant is the propane gas, C₃H₈ while the percentage yield is 83.77%

Explanation:

Here we have

Propane gas with molecular formula C₃H₈, molar mass  = 44.1 g/mol combining with O₂ as follows

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Therefore, 1 mole of C₃H₈  combines with 5 moles of O₂ to produce 3 moles CO₂ and 4 moles of H₂O

Mass of propane = 0.1240 kg = 124.0 g

Number of moles of propane = mass of propane/(molar mass of propane)

The number of moles of propane = 124/44.1 = 2.812 moles

The molar mass of CO₂ = 44.01 g/mol

Mass of CO₂ = 0.3110 kg = 311.0 g

Therefore, number of moles of CO₂ = mass of CO₂/(molar mass of CO₂)

The number of moles of CO₂ = 311.0 kg/ 44.01 g/mol = 7.067 moles

Therefore, since 1 mole of propane produces 3 moles of CO₂, 2.812 moles of propane will produce 3 × 2.812 moles or 8.44 moles of CO₂

Therefore;

The limiting reactant is the propane gas, C₃H₈, since the oxygen is in excess

Hence

The \ percentage \ yield = \frac{Actual \, yield}{Theoretical \, yield} \times 100 = \frac{7.067}{8.44} \times 100 = 83.77 \%

The percentage yield = 83.77%.

7 0
3 years ago
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