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Elodia [21]
3 years ago
14

Multiply. Type your answer in the box. Do not use any spaces. (–9) x (+2) =

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

-18 because 9 times 2 is 18 but because you're multiplying a negative with a positive it equals -18

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the margins of a page are usually expressed in decimal parts of an inch. Using the given​ figure, how long is each typed line on
Marta_Voda [28]
The answer is .5 of an inch
7 0
3 years ago
Gianna has a two $3,000 one year CDs at different banks. Each compounds
sertanlavr [38]

Answer:

Option D

Step-by-step explanation:

To calculate compound interest we will use the formula :

A=P(1+\frac{r}{n})^{nt}

Where,

A = Amount on maturity

P = Principal amount = $3000

r = rate of interest = 8.4% = 0.084

n = number of compounding period = Monthly = 12

t = time = 1 year

Now put the values in the formula.

A=3000(1+\frac{0.08}{12})^{(12)(1)}

   = 3000(1+0.007)^{12}

   = 3000(1.007)¹²

   = 3000 × 1.08731066

   = 3261.93198 ≈ $3261.93

While the other bank compounds interest daily.

Therefore, n = 365

Now put the values in the formula with n = 365

=3000(1+\frac{0.084}{365})^{(365)(1)}

=3000(1+0.00023014)^{365}

=3000(1.00023014)^{365}

= 3000 × 1.08761958

= 3262.85874 ≈ $3262.86

Difference in the ending balance = 3262.86 - 3261.93

                                                       = $0.93

The difference in the ending balances of both CDs after one year would be $0.93.

8 0
4 years ago
12, 15, 10, 15, 11, 12, 15.
malfutka [58]

Answer:

1. ≈ 12.85

2. 15

3. -38

4. 41 miles

5. 88

Step-by-step explanation:

3 0
3 years ago
Hard math question!
luda_lava [24]
First, let me show you some notation.

To show a matrix is an inverse of another matrix, we write A^{-1}

-1 is not an exponent. It just shows that a matrix is an inverse of another matrix.

For a 2x2 matrix, we can get the inverse by first making b and c negatives and swap the positions of a and d.

Then multiply each entry in the matrix by 1 divided by the determinant.

\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]^{-1} = 
  \frac{1}{ad - bc}\left[\begin{array}{ccc}d&{-b}\\{-c}&a\end{array}\right] =  \\  \\ \\ \left[\begin{array}{ccc}d(\frac{1}{ad-bc})&{-b}(\frac{1}{ad-bc}) \\ {-c}(\frac{1}{ad-bc}) &a(\frac{1}{ad-bc}) \end{array}\right]

I hope this helped!
8 0
3 years ago
Find the slope of this graph. Screenshot given.
aleksklad [387]
It would be 4 I think
6 0
3 years ago
Read 2 more answers
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