Kinesha collects data about the eye colors of students in her science class.

1 answer:

8 0

You would need to give me the data to answer your question, but I can give you the definitions of the measures of variation!

The Mode is the number that repeats most often, (Ie. 1,2,2,3,4,5 the mode would be 2 because it appears twice-more than any other number)

The Mean is the average of the set of numbers(lets say we have 1,2,3,4,5. you would add them all up and divide by the number of figures: 1+2+3+4+5=15. 15 divided by 5[there are 5 numbers total] equals 3.)

The median is the middle number(Ie. 1,2,3,4,5 the median is 3 because it is in the middle.) If there are 2 middle numbers(Ie. 1,2,3,4,5,6) you take the two middle numbers(3 and 4) and find the mean of them(3+4=7, 7/2=3.5)

You might be interested in

A student writes "the quotient of 5 and x" to describe the algebraic expression -

pashok25 [27]

For this case we have to:

$\frac {a} {b} = c$

Where:

a: It's the Dividend

b: It is the Divider

c: Is the Quotient

Thus, the expression "the quotient of 5 and x" can be represented as:

$\frac {5} {x} = y$

Where "y" is the quotient of 5 and x.

ANswer:

$\frac {5} {x} = y$

5 0

3 years ago

please solve for the function and the function only for both of these problems for 10 points! thank you so much! :)

lesya692 [45]

Answer:

y = 5x + 10

y = 0.75x + 4

Step-by-step explanation:

3 0

3 years ago

The isotope cobalt-60 has a nuclear mass of 59.933820 u

Anit [1.1K]

To start this question, we should know what is the atomic number of cobalt. The atomic number (the number of protons) of Cobalt is Z =27.

Now, we know that a Cobalt 60 isotope means an isotope of Cobalt whose Atomic Mass is 60.

Thus, in a Cobalt 60 isotope, the number of neutrons in the nucleus are

$60-Z=60-27=33$

From the question we know that the given nuclear mass is 59.933820 u.

Now, the mass defect of Cobalt 60 can be easily calculated by adding the masses of the protons and the neutrons as per our calculations and subtracting the given nuclear mass from it.

Thus,

Mass Defect = (Number of Protons Mass of Proton given in the question) + (Number of Neutrons Mass of Neutron given in the question)-59.933820 u

$\therefore 27\times 1.007825+33\times 1.008665-59.933820=0.5634 u$