3 years ago

Please Help!!!

1 answer:

5 0

By synthetic division,

-5 | 1 -6 -42 79
. | -5 55 -65
- - - - - - - - - - - - - - - - -
. | 1 -11 13 14

$\implies\dfrac{x^3-6x^2-42x+79}{x+5}=x^2-11x+13+\dfrac{14}{x+5}$
$\implies x^3-6x^2-42x+79=(x^2-11x+13)(x+5)+14$

When $x=-5$ , you're left with a remainder of 14.

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