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Neporo4naja [7]

2 years ago

11

Can you please help me answer this question?

2 answers:

Morgarella [4.7K]2 years ago

7 0

If the question is who had the fastest time its Britney

frozen [14]2 years ago

6 0

cant see the question

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A warehouse employs 22 workers on first shift and 14 workers on second shift. Eight workers are chosen at random to be interview

lara [203]

36 all together.
22 first
14 second
8 random chosen

A) all first shift:
One is pulled 22/36
Second is pulled 21/35
Third is pulled 20/34
Fourth 19/33
Fifth 18/32
Sixth 17/31
Seventh 16/30
Eighth 15/29

Multiply all those together
Probability of all first shift is 0.010567296996663
(That means it's not happening anytime soon lol)

B) one worker 14/36
Second 13/35
Third 12/34
Fourth 11/33
Fifth 10/32
Sixth 9/31
Seventh 8/30
Eighth 7/29

Multiply all those together
Probability of all second shift is 0.000099238805645
(That means it's likely to see 100x more picks of all first shift workers before you see this once.. lol)

C) 22/36
21/35
20/34
19/33
18/32
17/31

Multiply..
Probability.. 0.038306451612903

D) 14/36
13/35
12/34
11/33

X... p=0.016993464052288

Probably not correct, haven't done probability in years.

8 0

2 years ago

The steps for solving a proportioll.<br> 1.) What number is 70% of 45?

Evgesh-ka [11]

Answer:

P (0) =100%

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Charlotte has two job offers as a car sales person. The first job will pay her $600 a month plus 2% on the price of her car sale

Lana71 [14]

$40,000
Let x be the sales amount.
600+0.02x=1000+0.01x
x=$40,000

5 0

2 years ago

What simple interest rate would allow $6000 to grow to an amount of $14550 in 10 years?

Harman [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \: 14.25 \: \% \: }}}}}$

Step-by-step explanation:

Given,

Principal ( P ) = $ 6000

Amount ( A ) = $ 14550

Time ( T ) = 10 years

Rate ( R ) = ?

<u>Finding </u><u>the </u><u>Interest</u>

The sum of principal and interest is called an amount.

From the definition,

$\boxed{ \sf{Amount = \: Principal + Interest}}$

plug the values

⇒ $\sf{14550 = 6000 + Interest}$

Swap the sides of the equation

⇒ $\sf{6000 + Interest = 14550}$

Move 6000 to right hand side and change its sign

⇒ $\sf{Interest = 14550 - 6000}$

Subtract 6000 from 14550

⇒ $\sf{Interest = \: 8550 \: }$

Interest = $ 8550

<u>Finding </u><u>the </u><u>rate </u>

${ \boxed{ \sf{Rate = \frac{Interest \times 100}{Principal \times Time}}}}$

plug the values

⇒ $\sf{ Rate = \frac{8550 \times 100}{6000 \times 10} }$

Calculate

⇒ $\sf{Rate = \frac{855000}{60000} }$

⇒ $\sf{Rate = 14.25 \: \% \: }$

Hope I helped!

Best regards!!

8 0

2 years ago

Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?

Alekssandra [29.7K]

Answer:

See Explanation

Step-by-step explanation:

Given

New function: $y = 3 \cos(10 (x -\pi))$

We can assume the parent function to be:

$y = \cos (x)$

The new function can be represented as:

$y = A*\cos((\frac{2\pi}{B})(x-c))$

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

$y = A*\cos((\frac{2\pi}{B})(x-c))$ to $y = 3 \cos(10 (x -\pi))$

$A = 3$

$c = \pi$

$\frac{2\pi}{B} = 10$

Solve for B

$B = \frac{2\pi}{10}$

$B = \frac{\pi}{5}$

Using the calculated values of $A,\ B\ and\ c.$ This implies that, the following transformations occur on the parent function:

<em>Vertically stretched by </em> $3$ <em />
<em>Horizontally compressed by </em> $\frac{\pi}{5}$ <em />
<em>Right shifted by </em> $\pi$ <em />

5 0

2 years ago

Read 2 more answers