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photoshop1234 [79]
4 years ago
10

Simplify the exponents using the rules of exponents (54b^3/b^15)^2/3

Mathematics
1 answer:
Dovator [93]4 years ago
4 0
(\frac{54b^{3}}{b^{15}})^{\frac{2}{3}} = (\frac{54}{b^{12}})^{\frac{2}{3}} = \frac{(54)^{\frac{2}{3}}}{(b^{12})^{\frac{2}{3}}} = \frac{\sqrt[3]{54^{2}}}{\sqrt[3]{b^{24}}} = \frac{\sqrt[3]{2916}}{b^{8}} = \frac{9\sqrt[3]{4}}{b^{8}}
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A particle travels along the x-axis such that its velocity is given by v(t) = (t^0.7 + 4t) cos (t^2). What is the average accele
Airida [17]

It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.

The average acceleration of the particle over this interval is given by the average rate of change of v(t),

a_{\rm ave} = \dfrac{v(b) - v(a)}{b - a} = \boxed{\dfrac{(b^{0.7}+4b)\cos(b^2) - (a^{0.7}+4a)\cos(a^2)}{b - a}}

8 0
3 years ago
Determine the equation of the line that passes through the points of intersection of the graphs of the quadratic functions f(x)
timofeeve [1]

Answer:x-2y-2=0

Step-by-step explanation:

Given :

f(x) = x^2 - 4 \\ g(x) = - 3x^2 + 2x + 8

Point of intersection :

f(x)=g(x)\\x^2-4=-3x^2+2x+8\\4x^2-2x-12=0\\2x^2-x-6=0\\2x^2-4x+3x-6=0\\2x(x-2)+3(x-2)=0\\(x-2)(2x+3)=0\\x=2\,,\,\frac{-3}{2}

x=2\,;f(2)=2^2-4=0\\x=\frac{-3}{2}\,; f\left ( \frac{3}{2} \right )=\left ( \frac{3}{2} \right )^2-4=\frac{-7}{4}=-1.75

So, we have points \left ( 2,0 \right )\,,\,\left ( -1.5,-1.75\ \right )

Equation of line passing through two points \left ( x_1,y_1 \right )\,,\,\left ( x_2,y_2 \right ) is given by y-y_1=\frac{y_2-y_1}{x_2-x_1}\left ( x-x_1 \right )

Let \left ( x_1,y_1 \right )=\left ( 2,0 \right )\,,\,\left ( x_2,y_2 \right )=\left ( -1.5,-1.75\ \right )

So, equation is as follows :

y-0=\frac{-1.75-0}{-1.5-2}\left ( x-2 \right )\\y=\frac{-1.75}{-3.5}\left ( x-2 \right )\\y=\frac{1}{2}(x-2)\\2y=x-2\\x-2y-2=0

4 0
4 years ago
Jackson purchases a new car for $48,000. The car's value can be modeled by the
vekshin1

We have been given that Jackson purchases a new car for $48,000. The car's value can be modeled by the  following exponential function: y = 48000(0.76)^t where y represents the car's  value and t represents time in years. We are asked to find the decay rate as a percentage.

We know that an exponential decay function is in form y=a\cdot (1-r)^x, where,

y = Final value,

a = Initial value,

r = Decay rate in decimal form,

x = time.

Upon comparing our given function y = 48000(0.76)^t with standard decay function  y=a\cdot (1-r)^x, we can see that 1-r=0.76.

Let us solve for r.

1-1-r=0.76-1

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r=0.24

Let us convert 0.24 into percentage.

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Therefore, the decay rate is 24%.

8 0
3 years ago
6th grade math help me pleaseeee
Gnoma [55]

Answer:

1.4

Step-by-step explanation:

9.5+0.9t

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=9.5+-8.1

=1.4

3 0
3 years ago
Read 2 more answers
Find the surface area. ​
Marysya12 [62]

let's notice, this is a Cube, namely all equal sides, and mind you it has 6 sides, Check the picture below.

\stackrel{\textit{area of all 6 sides}}{6(9\cdot 9)\implies 486}

8 0
3 years ago
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