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torisob [31]
4 years ago
15

Jared’s abuela gave him $19 for his birthday. He bought $8.25 worth of candy and spent $4.25 on a new comic book. How much money

does Jared have left?
Mathematics
2 answers:
goldenfox [79]4 years ago
8 0

Answer:

$6.50

Step-by-step explanation:

Try to think of it in this way, your goal is to get to 19$.

add 4$ plus 8$ together and you get 12$.

now all you're missing is the cents. 25 plus 25 equals 50 cents. So 12$ and .50 cents add them together and you have 12.50.

Which means you only have $6.50 left.

Gemiola [76]4 years ago
4 0
Jared would have $6.50 left
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If you roll a standard six sided dice, what is the probability you will roll a four?
astra-53 [7]

Answer:

1/6

Step-by-step explanation:

There are 6 sides on a dice. Every time you roll you you will have one of those sides. So it is a 1 in 6 chance of you getting 4, meaning that the answer to this problem is 1/6

7 0
3 years ago
You can spend at most $60 on beads. A bag containing red beads costs $2 per bag. A bag containing blue beads costs $3 per bag. Y
nexus9112 [7]
For this case, the first thing we must do is define variables.
 We have then:
 x: number of blue beads
 y: number of red beads
 We now write the inequations system:
 3x + 2y  \leq  60

x\ \textgreater \  y
 Answer:
 a system of linear inequations that represents the situation is:
 3x + 2y \leq 60 x\ \textgreater \ y
8 0
3 years ago
Read 2 more answers
Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?
Anit [1.1K]

Answer:

\dfrac{p^{7} q}{160}

Step-by-step explanation:

\dfrac{(4p^-4 q)^-2}{10pq^-3} =

= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}

= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}

= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}

= \dfrac{1}{160}p^{7} q

= \dfrac{p^{7} q}{160}

4 0
3 years ago
Read 2 more answers
Please help. Thank you!
katrin2010 [14]

Answer:

3a. ⇒ 2700 cm³

3b. ⇒ 72,900 cm³

3c. ⇒ 27

Step-by-step explanation:

3a.

∵ The model in a shape of square pyramid

∴ Its volume = base area × height

∵ Base shaped square with side length 15 cm

∴ Area of base = 15 × 15 = 225 cm²

∵ The model height = 12 cm

∴ She needs = 225 × 12 = 2,700 cm³ of plaster

3b.

∵ Each dimension in the actual stage = 3 times the model

∴ The side of the square base = 15 × 3 = 45 cm

∴ The height = 12 × 3 = 36 cm

∴ The area of the base = 45 × 45 = 2,025 cm²

∴ She needs = 2025 × 36 = 72,900 cm³ of plaster

3c.

∵ Each length in the actual stage is 3 times the model

∴ The volume of the actual stage = (3)³ the volume of the model

∴ The volume of the actual stage = 27 the volume of the model

<em>To check your answer:</em>

Volume actual ÷ Volume model = 72,900 ÷ 2700 = 27

3 0
3 years ago
What fraction is equivalent to -3/2
NARA [144]

Answer:

8/12

Step-by-step explanation:

Hope it’s right

4 0
3 years ago
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