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gulaghasi [49]
3 years ago
7

n 1895, the first Putting Green Championship was held. The winner’s prize money was $200. In 2016, the winner’s check was $1,480

,000. a. What was the percentage increase per year in the winner’s check over this period? (Do not round intermediate calculations and enter your answer as a percent rounded to 2 decimal places, e.g., 32.16.) b. If the winner’s prize increases at the same rate, what will it be in 2043?
Mathematics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

  • 7.64% per year
  • $10,805,480 . . . . rounded to 7 significant figures

Step-by-step explanation:

Using 2016 as a reference (t=0), the exponential equation for winnings can be written as ...

  w(t) = 1480000×(1480000/200)^(t/121)

where 1480000 is the winnings in the reference year, and the ratio 1480000/200 is the ratio of winnings increase over the 121 years from 1895 to 2016.

This can be approximated by ...

  w(t) ≈ 1,480,000×1.07640850764^t

In this form, we can see that the annual percentage increase is ...

  1.0764 -1 = 7.64%

__

Then the winner's check in 2043, 27 years after 2016, is predicted to be ...

  w(27) = $1,480,000×(1.0764...)^27 ≈ $10,805,478.41 ≈ $10,805,000

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Using the z-distribution, as we have the standard deviation for the population, it is found that the smallest sample size required to obtain the desired margin of error is of 77.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

In which:

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The margin of error is given by:

M = z\frac{\sigma}{\sqrt{n}}

In this problem, we have that the parameters are given as follows:

M = 3, z = 1.645, \sigma = 16.

Hence, solving for n, we find the sample size.

M = z\frac{\sigma}{\sqrt{n}}

3 = 1.645\frac{16}{\sqrt{n}}

3\sqrt{n} = 1.645 \times 16

\sqrt{n} = \frac{1.645 \times 16}{3}

(\sqrt{n})^2 = \left(\frac{1.645 \times 16}{3}\right)^2

n = 76.97

Rounding up, the smallest sample size required to obtain the desired margin of error is of 77.

More can be learned about the z-distribution at brainly.com/question/25890103

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