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3 years ago

Between 20 to 35 degrees north latitude, and also between 20 to 35 degrees south latitude are found:

Mathematics

1 answer:

myrzilka [38]3 years ago

5 0

Answer:

Following are the solution to the given question:

Step-by-step explanation:

Its area includes all Sahara's locations in North Africa, South Arabia, Iran's and Iraq's larger parts, North-Western India, California throughout the United States, South Africa but most of Australia.

Half-arid temperatures include places like the Utah, Montana, and Gulf Coastal regions of sagebrush. Also, it comprises regions in Iceland, Russia, Scandinavia, Greenland, and Northeast India. Semi-arid thankless than tube called per year of rain and up to 20 inches per year at much more than arid deserts.

Regions from of the latitude of 25° to 35° usually develop desert, because air sinks and is heated under pressures in this area. The world's dry and semi-arid desert regions are between 20°C and 35°C north latitude and between 20°C and 35°C South latitude.

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Ludmilka [50]

Answer:

A, x>3

Step-by-step explanation:

You solve the equation as normal by crossing out both sides and getting what equals to x, but since you divided by a negative the sign flips and you are left with your answer. Hope this helps!

8 0

3 years ago

Use undetermined coefficient to determine the solution of:y"-3y'+2y=2x+ex+2xex+4e3x

Kitty [74]

First check the characteristic solution: the characteristic equation for this DE is

r ² - 3r + 2 = (r - 2) (r - 1) = 0

with roots r = 2 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(2x) + C₂ exp(x)

For the ansatz particular solution, we might first try

y (part.) = (ax + b) + (cx + d) exp(x) + e exp(3x)

where ax + b corresponds to the 2x term on the right side, (cx + d) exp(x) corresponds to (1 + 2x) exp(x), and e exp(3x) corresponds to 4 exp(3x).

However, exp(x) is already accounted for in the characteristic solution, we multiply the second group by x :

y (part.) = (ax + b) + (cx ² + dx) exp(x) + e exp(3x)

Now take the derivatives of y (part.), substitute them into the DE, and solve for the coefficients.

y' (part.) = a + (2cx + d) exp(x) + (cx ² + dx) exp(x) + 3e exp(3x)

… = a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)

y'' (part.) = (2cx + 2c + d) exp(x) + (cx ² + (2c + d)x + d) exp(x) + 9e exp(3x)

… = (cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

Substituting every relevant expression and simplifying reduces the equation to

(cx ² + (4c + d)x + 2c + 2d) exp(x) + 9e exp(3x)

… - 3 [a + (cx ² + (2c + d)x + d) exp(x) + 3e exp(3x)]

… +2 [(ax + b) + (cx ² + dx) exp(x) + e exp(3x)]

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

… … …

2ax - 3a + 2b + (-2cx + 2c - d) exp(x) + 2e exp(3x)

= 2x + (1 + 2x) exp(x) + 4 exp(3x)

Then, equating coefficients of corresponding terms on both sides, we have the system of equations,

x : 2a = 2

1 : -3a + 2b = 0

exp(x) : 2c - d = 1

x exp(x) : -2c = 2

exp(3x) : 2e = 4

Solving the system gives

a = 1, b = 3/2, c = -1, d = -3, e = 2

Then the general solution to the DE is

y(x) = C₁ exp(2x) + C₂ exp(x) + x + 3/2 - (x ² + 3x) exp(x) + 2 exp(3x)

4 0

2 years ago

Picture attached!! help!

o-na [289]

C your welcome tell me if u need more help

3 0

3 years ago

Drag each statement to the correct category. Classify the sentences based on whether they are or are not statements. Prime numbe

Archy [21]

Answer:

1. Prime numbers are easier to count. (Not a statement)

2.Irrational numbers can be written as fractions. (Statement)

3. Natural numbers can be negative. (Statement)

4. Addition is the simplest mathematical operation. (Not a Statement)

5. Equilateral triangles are quicker to construct than scalene triangles. (Not a statement)

6. The set of real numbers is infinite. (Statement)

i hope it will help you!

6 0

2 years ago

Dan has the same number of nickels and dimes in his piggy bank. If the total amount of those coins is $0.90, how many of each co

SpyIntel [72]

Answer:

Step-by-step explanation:

We can start by defining a couple things.

x = amount of nickels

y = amount of dimes

Since he has the same amount of each, we can say this.

x = y

And because we know it totals 0.90, we can say this.

0.05x + 0.10y = 0.90

then, we substitute and get this.

0.05x + 0.10x = 0.90

Simplify.

0.15x = 0.90

Divide both sides by 0.15.

x = 6

So we have 6 nickels, and they both are the same, so we have 6 dimes.

4 0

3 years ago