The value of t that makes the factor e^(.032t) have the value of 2 can be found using logarithms.
2 = e^(0.032t)
ln(2) = ln(e^(0.032t)) = 0.032t
t = ln(2)/0.032 ≈ 21.66
It would take 21.66 years for the cost to double.
Answer: See each part below.
1) A, B, and C are the coefficients in order when it equals 0. Move over the 4 and you have 5, 9, -4 or Choice B.
3) If you graph the equation, it will be above the x-axis. Therefore, it has no roots. Choice D
4) Choice A is correct. Use the coefficients: A = 4, B = 3, C = -10. Simply plug those into the quadratic equation and you will get -2 and 1.25.
At 6pm, the temperature is -17 degrees Fahrenheit.
For a function to be odd f(-x)=-f(x).
1) putting x as -x
f(-x)= -x^3+x^2 = -f(x)
Thus, this is an odd function.
2) Following the same procedure,
f(-x)= -x^5+3x^3-2x =-f(x)
Thus, this is an odd function.
3) Again,
f(-x)= -4x-9 = -f(x)
This also is an odd function.
Hope this helps :)
The answer is 8%
Compound interest formula is:
A = P(1 + r/n)ⁿˣ
A - the final amount
P - the initial amount
r - interest rate
n - number of compoundings per year
x - time period
We have:
A = <span>$1389.08
P = </span><span>$1000
r = ?
n = 2 (it is semiannual)
x = 4
</span>A = P(1 + r/n)ⁿˣ
1389.08 = 1000(1 + r/2)²*⁴
1389.08 = 1000(1 + r/2)⁸
(1 + r/2)⁸ = 1389.08/1000
(1 + r/2)⁸ = 1.389
![\sqrt[8]{(1 + \frac{r}{2} ) ^{8}} = \sqrt[8]{1.389} \\ 1 + \frac{r}{2} =1.04 \\ \frac{r}{2} = 1.04-1 \\ \frac{r}{2} = 0.04 \\ r = 2*0.04 =0.08](https://tex.z-dn.net/?f=%20%5Csqrt%5B8%5D%7B%281%20%2B%20%20%5Cfrac%7Br%7D%7B2%7D%20%29%20%5E%7B8%7D%7D%20%20%20%3D%20%20%5Csqrt%5B8%5D%7B1.389%7D%20%20%5C%5C%20%0A1%20%2B%20%20%5Cfrac%7Br%7D%7B2%7D%20%3D1.04%20%5C%5C%20%0A%20%5Cfrac%7Br%7D%7B2%7D%20%3D%201.04-1%20%5C%5C%20%0A%20%5Cfrac%7Br%7D%7B2%7D%20%3D%200.04%20%5C%5C%20%0Ar%20%3D%202%2A0.04%20%3D0.08)
r = 0.08 = 8/100 = 8%