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IgorLugansk [536]
3 years ago
15

jim is selling greeting cards at a booth at a folk fair. he will be paid $12 plus $2 for each box that he sells how many boxes m

ust he sell in order to make at least $42
Mathematics
2 answers:
3241004551 [841]3 years ago
8 0

Answer: 3 boxes

Step-by-step explanation:

If each box is 12, 3 Times 12 is 36 plus the 2 for each box gives you 42

poizon [28]3 years ago
7 0

Answer:

3 boxes because each box will make him 14 so 14 × 3 = $42

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What is the Factor of :<br> 10x + 15
lesantik [10]

Answer:

The factor of : 10x+15 is

Step-by-step explanation:

10x+15

5(2x+3)

5 0
3 years ago
HELP ME WITH THIS QUESTION PLZ
il63 [147K]

Step-by-step explanation:

step 1. (1) 5a +8c +4p = 57

(2) 9a +8c + 7p = 89

(3) 8a + 4c + 5p = 68.

step 2. this is a 3 variable system. solve the system.

step 3. eliminate c from (1) and (2) and also from (2) and (3). so you now have 4a + 3p = 32 and 7a + 3p = 47. now you have a two variable system

step 4. eliminate p by subtracting: 3a = 15 so a = 5.

step 5. if a = 5 then p = 4 ( plug into step 3)

step 6. if a = 5, p = 4, then c = 2 (plug into step 1).

step 7. apples = 5, pears = 4, cherries = 2.

5 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.7
Zinaida [17]

Answer:

(a) The probability that the sample average sediment density is at most 3.00 is 0.092.

    The probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b) The sample size must be at least 77.

Step-by-step explanation:

The random variable <em>X</em> ca be defined as the sediment density (g/cm) of a specimen from a certain region.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 2.7 and standard deviation, <em>σ</em> = 0.75.

(a)

A random sample of <em>n</em> = 25 specimens is selected.

Compute the probability that the sample average sediment density is at most 3.00 as follows:

Apply continuity correction:

P(\bar X\leq 3.00)=P(\bar X

                    =P(\bar X

                    =P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

                    =P(Z

Thus, the probability that the sample average sediment density is at most 3.00 is 0.092.

Compute the probability that the sample average sediment density is between 2.70 and 3.00 as follows:

P(2.70

                                =P(0

*Use a <em>z</em>-table.

Thus, the probability that the sample average sediment density is between 2.70 and 3.00 is 0.477.

(b)

It is provided that:

P(\bar X\leq 3.00)\geq 0.99

P(\bar X

P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}

P(Z

The value of <em>z</em> for the probability above is

<em>z</em> ≥ 2.33

Compute the value of <em>n</em> as follows:

\frac{|2.50-2.70|}{0.75/\sqrt{n}}\geq 2.33

\frac{|-0.20|}{2.33}\geq \frac{0.75}{\sqrt{n}}

\sqrt{n}\geq \frac{0.75\times 2.33}{|-0.20|}\\\sqrt{n}\geq 8.7375\\n\geq 76.3439\\\approx n\geq 77

Thus, the sample size must be at least 77.

8 0
3 years ago
A ladder is leaning up against a house. The ladder is 20 feet long and the base of the ladder is 12 feet away from the house. Ho
MrRa [10]

Answer:

16 feet

Step-by-step explanation:

The length of the ladder=20 feet

Distance from the base of the ladder to the house = 12 feet

You will notice that a wall is vertical and the ladder makes an angle with the horizontal ground(making it the hypotenuse). This is a right triangle problem.

To find the how far up the house can the ladder can reach, we simply find the third side of the right triangle.

From Pythagoras theorem

Hyp^2=Opp^2+Adj^2\\20^2=12^2+Adj^2\\Adj^2=400-144\\Adj^2=256\\Adj=\sqrt{256}=16

The third side of the right triangle is 16. Therefore the ladder leans 16 feet from the ground.

8 0
4 years ago
Read 2 more answers
How do you solve <br>2v+18=16-4(v+7)
Andreyy89
2v + 18 = 16 - 4(v + 7)

Simplify by removing the parenthesis.

2v + 18 = 16 - 4v - 28

Now, simply add 4v to both sides.

2v + 4v + 18 = 16 - 28

Simplify.

6v + 18 = -12

Now, subtract 18 from both sides.

6v = -12 - 18

Simplify.

6v = -30

Finally, divide both sides by 6.

6v ÷ 6 = 30 ÷ 6

Simplify.

v = 5

~Hope I helped!~

4 0
3 years ago
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