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3 years ago

Can someone please help me with question 7 8 and 9 please

Mathematics

1 answer:

Svetach [21]3 years ago

4 0

Answer:

7. n (Division sign) -5+1<7 = n<11 8. n (division sign) 3-2>-12= n>11 9. -2 x n-6>-18= n>-10

Step-by-step explanation:

I think this is right

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A new lawn has a perimeter of 278ft. And a width of 64ft. A bag of grass seed will cover 384ft of ground. How many bags of grass

Anit [1.1K]

Answer:

13 bags

Step-by-step explanation:

Area of the lawn: A=lw

w= 64 ft

P= 2(l+w)= 278 ft ⇒

l= 278/2- 64= 75 ft

A= 64*75= 4800 ft²

bags of seed required:

4800/384= 12.5 so 13 full bags needed

7 0

3 years ago

Find function inverse of f? F(x)=x+2/7

nignag [31]

Answer:

f’(x) = x -2/7

Step-by-step explanation:

Let f(x)= y

Thus;

y = x + 2/7

x = y-2/7

So the inverse f’(x) = x - 2/7

6 0

3 years ago

Mr johnson's students want to know his age. He tells them that this year his age is a multiple of 9, and next year it will be a

vladimir1956 [14]

Answer:

He is 27 years old.

Step-by-step explanation:

27 is a multiple of 9 (9 x 3)

28 comes after, and is a multiple of 4 (4 x 7)

Hope this answer helps you!! :)

8 0

2 years ago

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0

2 years ago

find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i

tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

m = mass of box = 40 lb,
g = acceleration due to gravity = 32 ft/s² and
h = height of incline = LsinФ where
L = length of incline = 100 ft and
Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0

1 year ago