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3 years ago

What do the following two equations represent? • y-8=1/5(x+5) • y-8=-1/2(x+5)

Mathematics

1 answer:

tangare [24]3 years ago

8 0

Answer:

Intersecting, but not perpendicular lines

When you graph it, it isn't gonna be apart, its gonna be intersecting

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4(x-2)-5x>-1 grater or equal I’m bad at this

Lunna [17]

X<-7 so the answer would be greater*

4 0

3 years ago

Help please! I would really appreciate it!!!

Nutka1998 [239]

Answer:

the output is n+5

Step-by-step explanation:

3+5

4+5

8+5

n+5

6 0

3 years ago

A soccer goal should be centered in a penalty area. The penalty area is 17 yards wide. The goal is 5 yards wide. How many yards

hichkok12 [17]

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2 years ago

The function f(x)=g(x), where f(x)=2x-5 and g(x)=x^2-6. The table below shows the process of solving using successive approximat

valkas [14]

Answer:

The positive solution is 2.4.

Step-by-step explanation:

The given functions are

$f(x)=2x-5$

$g(x)=x^2-6$

It is given that

$f(x)=g(x)$

$2x-5=x^2-6$

$0=x^2-6-2x+5$

$0=x^2-2x-1$

The quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{2\pm \sqrt{(2)^2-4(1)(-1)}}{2(1)}$

$x=\frac{2\pm \sqrt{8}}{2}$

$x=\frac{2\pm 2\sqrt{2}}{2}$

$x=\frac{2(1\pm \sqrt{2})}{2}$

$x=1\pm \sqrt{2}$

$x=2.4,-0.4$

Therefore the positive solution is 2.4.

6 0

3 years ago

Read 2 more answers

A crowd of people stood on both sides of the street to view a 4th of July Parade.

Dmitriy789 [7]

Given :

Length of parade , $L = 3\ miles=3\times 5280\ miles = 15840\ miles$ .

Breadth of parade , $B=2\times 15=30\ ft$ .

5 people can fit into a $25\ ft^2$ area.

1 mile = 5280 ft .

To Find :

The size of the crowd.

Solution :

Area of parade ,

$A=15840\times 30\ ft^2\\\\A=475200\ ft^2$

Also , 5 people can fit in $25\ ft^2$ area .

So , number of people fit in A is :

$n = \dfrac{475200\times 5}{25}\\\\n=95040$

Therefore , 95040 can fit in the parade .

Hence , this the required solution .

6 0

2 years ago