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MrRa [10]
3 years ago
8

Max is taking out a 5.1% load in order to purchase the 17,000 car the length of the loan is five years how much will the pay in

interest
Mathematics
2 answers:
katrin2010 [14]3 years ago
6 0
I don't which interest it is
Simple interest=
17000 \times 5.1\% \times 5
Compound interest=
17000(1 +  {5.1\%})^{5}
then solve

Alenkasestr [34]3 years ago
4 0

Answer: 4,335

Step-by-step explanation:

To calculate max interest, we simply us the simle interst formular;

Simple interest = P × R ×T / 100

where p= principal

R = Rate

T= time (in years)

principal = 17, 000 Rate = 5. 1 and the time= 5

Simple interest =P × R ×T / 100

= 17000 × 5. 1 ×5 / 100

(The two zeros at the denominator will cancel two of the zeros at the numerator)

simple interest = 170 × 5. 1 × 5

=4335

Therefore the pay in interest is 4335

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6 times a number is 27 less than the square of that number. Find the positive solution.
Verdich [7]

Let x = your number.

6x = x^2 - 27. Subtract 6x from each side.

0 = x^2 - 6x - 27. Factor

0 = (x-9) (x+3). Set each term equal to zero

(x+3) = 0. Subtract 3 from each side.

x = -3. This is the negative solution.

(x-9) = 0. Add 9 to each side.

x = 9. This is the positive solution.

6 0
3 years ago
Write each number in standard form.<br>4. 80,000,000 + 4,000,000 + 100 + 8 the answer ​
dimaraw [331]

Answer:

84,000,108

Step-by-step explanation:

8 0
3 years ago
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Since at t=0, n(t)=n0, and at t=∞, n(t)=0, there must be some time between zero and infinity at which exactly half of the origin
Airida [17]
Answer: t-half = ln(2) / λ ≈ 0.693 / λ

Explanation:

The question is incomplete, so I did some research and found the complete question in internet.

The complete question is:

Suppose a radioactive sample initially contains N0unstable nuclei. These nuclei will decay into stable nuclei, and as they do, the number of unstable nuclei that remain, N(t), will decrease with time. Although there is no way for us to predict exactly when any one nucleus will decay, we can write down an expression for the total number of unstable nuclei that remain after a time t:

N(t)=No e−λt,

where λ is known as the decay constant. Note that at t=0, N(t)=No, the original number of unstable nuclei. N(t) decreases exponentially with time, and as t approaches infinity, the number of unstable nuclei that remain approaches zero.

Part (A) Since at t=0, N(t)=No, and at t=∞, N(t)=0, there must be some time between zero and infinity at which exactly half of the original number of nuclei remain. Find an expression for this time, t half.

Express your answer in terms of N0 and/or λ.

Answer:

1) Equation given:

N(t)=N _{0} e^{-  \alpha  t} ← I used α instead of λ just for editing facility..

Where No is the initial number of nuclei.

2) Half of the initial number of nuclei: N (t-half) =  No / 2

So, replace in the given equation:

N_{t-half} =  N_{0} /2 =  N_{0}  e^{- \alpha t}

3) Solving for α (remember α is λ)

\frac{1}{2} =  e^{- \alpha t} &#10;&#10;2 =   e^{ \alpha t} &#10;&#10; \alpha t = ln(2)

αt ≈ 0.693

⇒ t = ln (2) / α ≈ 0.693 / α ← final answer when you change α for λ




4 0
3 years ago
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mixas84 [53]

Answer:

x=72

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Step-by-step explanation:

1st question. y=54 because it is a bisector of the 108 degree angles. (a polygon's interior angles add to number of sides minus 2 times 180)

There are two ys, so they add up to 108. A triangle's interior angles add to 180. 180-108 =72 x=72

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y still equals 54

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The triangles shown below must be congruent.
Schach [20]
The answer is true :))))
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