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Volgvan
3 years ago
15

What is the inequality's answer −8x+44≥60 AND−4x+50<58

Mathematics
2 answers:
mixas84 [53]3 years ago
5 0

There aren't any solutions.

Vadim26 [7]3 years ago
5 0

Answer:

No solutions

Step-by-step explanation:

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What is the equation of the line that passes through the point <br> (−3,5) and has a slope of -2?
GenaCL600 [577]

Answer:

y = -2x-1

Step-by-step explanation:

y = -2x+b

5 = -2(-3)+b

5 = 6+b

-1 = b

3 0
3 years ago
Need some math help. I tried but I’ve already done over fifty questions. Thanks!
DENIUS [597]

Answer:

6a

Step-by-step explanation:

  AB = √[(3a - -3a)² + (0)²]

⇒ AB = √[(3a + 3a)² + (0)²]

⇒ AB = √[(6a)² + (0)²]

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3 years ago
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4 0
3 years ago
Suppose that the functions q and r are defined as follows.
satela [25.4K]

Answer:

(r o g)(2) = 4

(q o r)(2) = 14

Step-by-step explanation:

Given

g(x) = x^2 + 5

r(x) = \sqrt{x + 7}

Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

g(x) = x^2 + 5

g(2) = 2^2 + 5

g(2) = 4 + 5

g(2) = 9

Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

Next, we calculate g(r(2))

Substitute 3 for r(2)in g(r(2))

g(r(2)) = g(3)

g(x) = x^2 + 5

g(3) = 3^2 + 5

g(3) = 9 + 5

g(3) = 14

Hence:

(q o r)(2) = 14

8 0
2 years ago
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