You can’t simplify it any further. 288 1/4 is already simplified.
Answer: Tiffany by 1/12 of a mile
Step-by-step explanation:
Find the common denominator and compare both of them
Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean
and standard deviation 
Sample size, n = 37
Standard Deviation =

P(taxi and takeoff time will be less than 320 minutes)

Calculation the value from standard normal z table, we have,

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
Answer: 2000 tickets were sold
Step-by-step explanation:
8000 divided by 40 percent is 200
Answer:
B. 12.5
Step-by-step explanation:
We have the lowe confidence interval = 185
The upper confidence interval = 210
Mean of X = (lower confidence + upper confidence interval)/2
Mean of X = 185 + 210/2
= 197.5
The margin of error = the upper confidence interval - mean of X
= 210-197.5
= 12.5